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Aleksandr [31]
2 years ago
7

Bella sanchez's budget and expenditure for personal items during the month of july is shown. how much less did bella spend than

she budgeted?
Mathematics
1 answer:
Rashid [163]2 years ago
7 0
<span>The question here is how much less Bella spent in July than she budgeted. So firstly we have to know how much she budgeted and how much she spent in order to know the difference. Her total budgeted money is equal to $110. On the other hand, her total expenditure is equal to $85.50. So the difference between the two amounts is $24.5.</span>
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the size of a rectangular computer screen is determined by the length of its diagonal. tom buys a 52cm screen that is 33 cm high
Snowcat [4.5K]

Answer:

40.20cm approx

Step-by-step explanation:

Step one

given data

We are told that the dimension of a computer screen

diagonal= 52 cm

height= 33cm

Length = ?

Required

The length of the base of the screen

Step two

Let us use Pythagoras theorem to find the length of the base

Hyp^2= Opp^2+ Adj^2

52^2= 33^2+ L^2

2704= 1089+L^2

L^2= 2704-1089

L^2= 1615

L=√1615

L= 40.20cm approx

<u>The length is 40.20cm approx.</u>

8 0
2 years ago
3. Who set up their equation correctly for the following question?
melisa1 [442]
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5 0
2 years ago
Demand for Tablet Computers The quantity demanded per month, x, of a certain make of tablet computer is related to the average u
soldier1979 [14.2K]

x = f ( p ) = \frac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } } \\\\ \qquad { p ( t ) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \quad ( 0 \leq t \leq 60 ) }

Answer:

12.0 tablet computers/month

Step-by-step explanation:

The average price of the tablet 25 months from now will be:

p ( 25) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { 25 } } + 200 \\= \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \times 5 } + 200\\\\=\dfrac { 400 } { 1 + \dfrac { 5 } { 8 } } + 200\\p(25)=\dfrac { 5800 } {13}

Next, we determine the rate at which the quantity demanded changes with respect to time.

Using Chain Rule (and a calculator)

\dfrac{dx}{dt}= \dfrac{dx}{dp}\dfrac{dp}{dt}

\dfrac{dx}{dp}= \dfrac{d}{dp}\left[{ \dfrac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } }\right] =-\dfrac{100}{9}p(810,000-p^2)^{-1/2}

\dfrac{dp}{dt}=\dfrac{d}{dt}\left[\dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \right]=-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}

Therefore:

\dfrac{dx}{dt}= \left[-\dfrac{100}{9}p(810,000-p^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}\right]

Recall that at t=25, p(25)=\dfrac { 5800 } {13} \approx 446.15

Therefore:

\dfrac{dx}{dt}(25)= \left[-\dfrac{100}{9}\times 446.15(810,000-446.15^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt {25} \right]^{-2}25^{-1/2}\right]\\=12.009

The quantity demanded per month of the tablet computers will be changing at a rate of 12 tablet computers/month correct to 1 decimal place.

8 0
2 years ago
Jeanne makes hair bows to sell at the craft fair. Each bow requires 1.5 yards of ribbon. If Jeanne wants to make 84 bows, how ma
mina [271]

Answer:

Jeanne must buy <u>378 feet</u> of ribbons to make 84 bows.

Step-by-step explanation:

Given:

Each bow required = 1.5 yards of ribbon

Number of bow to make = 84

We need to find the length of ribbon in feet to make 84 bows.

Solution:

First we will find length of ribbons in yards required to make 84 bows .

Now we know that;

1 bow =1.5 yards of ribbons

84 bows = length of ribbons in yards

By using Unitary method we get;

length of ribbons in yards  = 1.5\times 84 = 126\ yards

Now we know that;

1 yard = 3 feet

126 yard = length of ribbons in feet

Again by using Unitary method we get;

length of ribbons in feet to make 84 bows = 126 \times 3 = 378\ ft

Hence, Jeanne must buy <u>378 feet</u> of ribbons to make 84 bows.

7 0
2 years ago
Horizontal and parallel lines M Q and U R are intersected by 2 diagonal lines N S and P T to form triangle E G F. Line N S inter
juin [17]

Answer:

I think it is ∠PEQ  

Step-by-step explanation:

8 0
2 years ago
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