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emmainna [20.7K]
1 year ago
8

miguel is buying prizes for a raffle.he will buy one prize that costs 50$ and four prizes that cost 20$ for each . The remainder

of the prizes will cost 10$ . if migual can spend no more than 300$ on all the prizes , what is the largest total number of prizes he can buy for the raffle ? (no sales tax)​
Mathematics
1 answer:
barxatty [35]1 year ago
5 0

Answer:

answer is 22

Step-by-step explanation:

please pick the brainlest answer

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the dot plot above identifies the number of pets living with each of 20 families in an apartment building .what fraction of fami
harkovskaia [24]

Answer:

B. ⅕

Step-by-step explanation:

Fraction of families having more than 2 pets = families with pets of 3 and above ÷ total number of families in the apartment

From the dot plot above, 3 families have 3 pets, and 1 family has 4 pets.

Number of families with more than 2 pets = 3 + 1 = 4

Fraction of families with more than 3 pets = \frac{4}{20} = \frac{1}{5}

4 0
1 year ago
Please help me with this
shutvik [7]

Answer:

your answer is a and d

Step-by-step explanation:

5 0
2 years ago
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The value of good wine increases with age. Thus, if you are a wine dealer, you have the problem of deciding whether to sell your
Katyanochek1 [597]

Answer: 64 years

Step-by-step explanation:

Let assume the dealer sold the bottle now for $P, then invested that money at 5% interest. The return would be:

R1 = P(1.05)^t,

This means that after t years, the dealer would have the total amount of:

$P×1.05^t.

If the dealer prefer to wait for t years from now to sell the bottle of wine, then he will get the return of:

R2 = $P(1 + 20).

The value of t which will make both returns equal, will be;

R1 = R2.

P×1.05^t = P(1+20)

P will cancel out

1.05^t = 21

Log both sides

Log1.05^t = Log21

tLog1.05 = Log21

t = Log21/Log1.05

t = 64 years

The best time to sell the wine is therefore 64years from now.

7 0
2 years ago
If a plane can climb at 2,400 feet per minute, how many minutes are needed to climb to 60,000 feet?
fomenos

Answer:

b

Step-by-step explanation:

25 minutes

5 0
2 years ago
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Harper knows he is 50 yards from school. The map on his phone shows that the school is 34 inch from his current location. How fa
laila [671]

To solve this problem you must apply the proccedure shown below:

1. We know that 1 yard is 36 inches, therefore, 50 yards expressed in inches is:

(50)(36)=1800in

2. If he is 50 yards from school and the map shows that the school is 34 inches from his current location, when it shows 3 inches the real distance is:

\frac{(1800in)(3in)}{34in}=158.82in

3. If you can to express it in yards:

\frac{158.82}{36} =4.41 yd

Therefore, the answer is: 158.82 inches or 4.41 yards.

8 0
2 years ago
Read 2 more answers
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