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Marat540 [252]
1 year ago
9

How does number sense of fractions help when estimating sums and differences

Mathematics
1 answer:
noname [10]1 year ago
3 0
You don't add or subtract the denominator. when you compare fractions like 1/4 and 1/8 you have to find the factors that repusent that like 2×4=8 so 4 2 is ur awnser
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Mr. Malloy wants to make sure Amo and Javier get the best possible grade after five tests and can either give a grade based on t
joja [24]
The data has been properly arranged in tabular form and is shown below in the image.

First we need to find the mean and median of scores of both students.

1) For Amo:
Mean = \frac{97+92+89+55+90}{5}=84.6
Median = Middle Value when data is arranged in ascending order = 90

2) For Javier:
Mean =\frac{68+97+65+92+95}{5}=83.4
Median = Middle Value when data is arranged in ascending order = 92

For both the students, value of Median is larger then the mean. So in order to give the best possible grade Mr. Malloy should use the median score for both students.

8 0
2 years ago
Read 2 more answers
Roberto wants to display his 18 sports cards in an album. Some pages hold 2 cards and others hold 3 cards. How many different wa
Ratling [72]
<span>65 = number of different arrangements of 2 and 3 card pages such that the total number of card slots equals 18. 416,154,290,872,320,000 = number of different ways of arranging 18 cards on the above 65 different arrangements of page sizes. ===== This is a rather badly worded question in that some assumptions aren't mentioned. The assumptions being: 1. The card's are not interchangeable. So number of possible permutations of the 18 cards is 18!. 2. That all of the pages must be filled. Since the least common multiple of 2 and 3 is 6, that means that 2 pages of 3 cards can only be interchanged with 3 pages of 2 cards. So with that said, we have the following configurations. 6x3 card pages. Only 1 possible configuration. 4x3 cards and 3x2 cards. These pages can be arranged in 7!/4!3! = 35 different ways. 2x3 cards and 6x2 cards. These pages can be arranged in 8!/2!6! = 28 ways 9x2 card pages. These can only be arranged in 1 way. So the total number of possible pages and the orders in which that they can be arranged is 1+35+28+1 = 65 possible combinations. Now for each of those 65 possible ways of placing 2 and 3 card pages such that the total number of card spaces is 18 has to be multiplied by the number of possible ways to arrange 18 cards which is 18! = 6402373705728000. So the total amount of arranging those cards is 6402373705728000 * 65 = 416,154,290,872,320,000</span>
7 0
2 years ago
The cost of a parking permit consists of a one-time administration fee plus a monthly fee. A permit purchased for 12 months cost
LekaFEV [45]
12x50=600 so 60 left
15x50=750 so 60 left
so the administration fee is 60
5 0
2 years ago
Read 2 more answers
The quotient of 38 times a number and -4
nikdorinn [45]

Answer:

140y

Step-by-step explanation:

35 times a number times -4 is 35×y×(-4) which is -140y

4 0
1 year ago
Credit cards place a three-digit security code on the back of cards. What is the probability that a code starts with the number
ohaa [14]

Answer: 1/10

Step-by-step explanation: because there are 10 numbers (1,2,3,4,5,6,7,8,9, and 0)

7 0
1 year ago
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