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2 years ago

How does number sense of fractions help when estimating sums and differences

1 answer:

3 0

You don't add or subtract the denominator. when you compare fractions like 1/4 and 1/8 you have to find the factors that repusent that like 2×4=8 so 4 2 is ur awnser

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Maggie needs to spend at least six hours each week practicing the piano. She has already practiced three and one fourth hours th

Marta_Voda [28]

Let X equal the remaining time she needs to practice.

You would have 2x

The combined total needs to be 6 hours or greater.

You need to add the amount she already practiced to 2x.

Now you have: three and one fourth + 2x

This needs to be greater than or equal to 6.

Answer: three and one fourth + 2x ≥ 6

8 0

2 years ago

Read 2 more answers

A person is standing exactly 36 ft from a telephone pole. There is a 30° angle of elevation from the ground to the top of the po

nika2105 [10]

Answer:

20.78feet

Step-by-step explanation:

The question made us to understand that the man is standing and also there is angle of elevation, then we need to draw a right triangle having a base equal to 36 feet with an angle from the base to the top of the pole which is 30 degrees.

tan= opposite side / adjacent side

Let height of the pole =h

Tan(30)= h/36

But tan 30degree= 1/√3

h= 36 × 1/√3

h= 20.78feet

Therefore, the height of the pole= 20.78feet

CHECK THE ATTACHMENT FOR DETAILED FIGURE

7 0

2 years ago

Read 2 more answers

7. If SK = 13x - 5, KY= 2x + 9, and SY = 36-x, find each value.

sweet [91]

Answer:

SY=34, SK=21 and KY=13

Step-by-step explanation:

we have that

SY=SK+KY

substitute the given values

(36-x)=(13x-5)+(2x+9)

solve for x

36-x=15x+4

15x+x=36-4

16x=32

x=2

Find the value of SY

SY=(36-x)=36-2=34

Find the value of SK

SK=(13x-5)=13(2)-5=21

Find the value of KY

KY=(2x+9)=2(2)+9=13

5 0

2 years ago

G identify the solution of the recurrence relation an = 6an − 1 – 8an − 2 for n ≥ 2 together with the initial conditions a0 = 4,

maksim [4K]

Via the generating function method, let

$G(x)=\displaystyle\sum_{n\ge0}a_nx^n$

Then take the recurrence,

$a_n=6a_{n-1}-8a_{n-2}$

multiply everything by $x^n$ and sum over all $n\ge2$ :

$\displaystyle\sum_{n\ge2}a_nx^n=6\sum_{n\ge2}a_{n-1}x^n-8\sum_{n\ge2}a_{n-2}x^n$

Re-index the sums or add/remove terms as needed in order to be able to express them in terms of $G(x)$ :

$\displaystyle\sum_{n\ge2}a_nx^n=\sum_{n\ge0}a_nx^n-(a_0-a_1x)=G(x)-4-10x$

$\displaystyle\sum_{n\ge2}a_{n-1}x^n=\sum_{n\ge1}a_nx^{n+1}=x\sum_{n\ge1}a_nx^n=x\left(G(x)-a_0\right)=x(G(x)-4)$

$\displaystyle\sum_{n\ge2}a_{n-2}x^n=\sum_{n\ge0}a_nx^{n+2}=x^2\sum_{n\ge0}a_nx^n=x^2G(x)$

So the recurrence relation is transformed to

$G(x)-4-10x=6x(G(x)-4)-8x^2G(x)$
$(1-6x+8x^2)G(x)=4-14x$
$G(x)=\dfrac{4-14x}{1-6x+8x^2}=\dfrac{4-14x}{(1-4x)(1-2x)}=\dfrac1{1-4x}+\dfrac3{1-2x}$

For appropriate values of $x$ , we can express the RHS in terms of geometric power series:

$G(x)=\displaystyle\sum_{n\ge0}(4x)^n+3\sum_{n\ge0}(2x)^n=\sum_{n\ge0}\bigg(4^n+3\cdot2^n\bigg)x^n$

which tells us that

$a_n=4^n+3\cdot2^n$

3 0

2 years ago

Determine the rate of change for the equation. 6y = 8x - 40

natulia [17]

The answer is 4/3 thats the rate of change. up 3 over 4

4 0

2 years ago