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Zolol [24]
2 years ago
12

Answer Please!!!! 20 points<3

Mathematics
2 answers:
vlabodo [156]2 years ago
8 0

Answer:

Hello I Just had this problem. The answer IS A

Step-by-step explanation:

Tpy6a [65]2 years ago
5 0

Answer:

The correct option is C.

Step-by-step explanation:

It is given that the longest wall in Jessica’s actual room is 15 feet long.

From the scale model it is clear that longest wall in Jessica’s actual room is 11 inches.

Let the actual length of door be x ft.

\frac{11}{15}=\frac{1.75}{x}

x=\frac{1.75\times 15}{11}

x\approx 2.386

The length of door is approx 2.386 ft.

The area of the actual space in her room where furniture cannot be placed because of the door is equivalent to the area of semicircle with radius 2.386 ft.

A=\frac{\pi r^2}{2}

A=\frac{\pi 2.386^2}{2}

A=8.942

A\approx 9

The area of the actual space in her room where furniture cannot be placed because of the door is approx 9 ft. Therefore option C is correct.

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A company manufactures two products X and Y. Each product has to be processed in three departments: welding, assembly and painti
Tems11 [23]

Answer:

100x+120y = z

z= $ 63000

Step-by-step explanation:

Product               Welding          Assembly       Painting                Cont. to profit

X                              2x hours            3x hours          1xhour         =        $100x

Y                              3y hours            2y hours           1y hour        =       $120y

<u>                                                                                                 </u>

Total hours          1500 hours        1500 hours     550 hours

available

Let X represent product X

Let Y represent Product Y

2x + 3y = 1500

x + y = 550

y= 550-x

2x + 3(550-x) = 1500

2x + 1650- 3x = 1500

150 = x

y = 550-150

y = 400

Objective Function Z = 100x + 120y

Z = 100(150) + 120( 400)

Z = 15000+48000

Z = $63000

7 0
2 years ago
The heights (in cm) and arm spans (in cm) of 31 students were measured. The association between x(height) and y(arm span) is sho
abruzzese [7]

Answer:

27.385 cm longer would we expect Mike's arm span to be than George's.

Step-by-step explanation:

We have to find how many centimeters longer would we expect Mike's arm span to be than George's using the equation:

y= 4.5x + 0.977 x

where y= arm span

and x= height

Given:

Mike's height=x = 175 cm

so Mike's arm span= y= 4.5 x + 0.977 x

                                    = 4.5* (175) + 0.977* (175)

                                    = 787.5 + 170.975

                                    = 958.475 cm

George's height = x = 170 cm

so George's arm span= y= 4.5 x + 0.977 x

                                    = 4.5* (170) + 0.977* (170)

                                    = 765 + 166.09

                                    = 931.09 cm

Mike's arm span longer than George's = Mike's arm span - George's arm span

                                                                 = 958.475 - 931.09

                                                                 = 27.385 cm.

8 0
2 years ago
Of the 2000 students attending, every 5th student going into the basketball game is asked if the school should spend more money
MA_775_DIABLO [31]
The students would show no regard for the money being spent because it is not their money
8 0
2 years ago
Akinte, Chuck, Jenny, and Norma are all going to college next year.
Licemer1 [7]

Answer and explanation:

Akinye Reynoso

Chuck peningan

Norma van hee

Jenny olowski

Akinte is not going to the University of Memphis nor university of Sierra tech nor university of Penn valley but goes to St Mary just like Reynoso(his surname)

Chuck is not going to St Mary nor Sierra tech nor Penn valley but goes to Memphis just like pennigan

Norman does not go to Memphis nor Penn valley nor St Mary but goes to Sierra tech just like van hee

Jenny does not go to Sierra tech nor St Mary nor Memphis but goes for Penn valley just like olowski

3 0
2 years ago
What are these fractions in simplest form?
Anton [14]
\frac{16y^{3}}{20y^{4}} =  \frac{4}{5y}
\frac{6xy}{16y} =  \frac{3x}{8}
\frac{abc}{10abc} =  \frac{1}{10}
\frac{mn^{2}}{pm^{5}n} =  \frac{n}{pm^{4}}
\frac{12h^{3}k}{16h^{2}k^{2}} =  \frac{3h}{4k}
\frac{8x}{10y} =  \frac{4x}{5y}
\frac{24n^{2}}{28n} =  \frac{6n}{7}
\frac{30hxy}{54kxy}  =  \frac{5h}{9k}
\frac{5jh}{15jh^{3}} =  \frac{1}{3h^{2}}
\frac{20s^{2}t^{3}}{16st^{5}} =  \frac{5s}{4t^{2}}
8 0
2 years ago
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