<span>First of all, there should be coherence for the units of measurement -- either they are all meters or they are all ft. I would assume they are all ft.
The correct answer is 75 ft above. T
The explanation is the following: suppose the ground level is the x-axis, the 2 feet of the arch lie respectively on (0,0) and (100,0) on the ground level. Since the arch is 100ft high, the vertex of the parabola will be the point (100,100). Thus, we can find the equation describing the parabola by putting the three points we know in a system and we find that the equation of the parabola is y=(-1/100)x^2+2
To find the focus F, we apply the formula for the focus of a vertical axis parabola, i.e. F(-b/2a;(1-b^2+4ac)/4a).
By substituting a=-1/100, b=2 and c=0 into the formula, we find that the coordinates of the focus F are (100,75).
So we conclude that the focus lies 75ft above ground.</span>
m<ABD = 52 Given
BC bisects <ABD Given
m<ABC = m<CBD Definition of angle bisector.
m<ABC +m<CBD = m<ABD Angle addition postulate.
m<ABC +m<CBD = 52 Substitution
m<ABC + m<ABC= 52 Substitution
2m<ABC = 52 Combining like angles
m<ABC = 26 Division property of equality.
I all of those options are true
c(x)=9x+89
I know that you don't have the answer listed, but it is the correct answer.
