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2 years ago

If you increase your current quality score of 85% by 7%,

Mathematics

2 answers:

svlad2 [7]2 years ago

5 0

85 x 0.07 = 5.95

Total = 85 + 5.95 = 90.95%

Gennadij [26K]2 years ago

3 0

Answer:

90.95%

Step-by-step explanation:

It has been given that our current quality score is 85%. We are asked to find our new quality score after an increase of of 7%.

$\text{New score}=\text{Old score + Increase in old score}$

$\text{New score}=85+7\%\text{ of }85$

$\text{New score}=85+(\frac{7}{100}\times 85)$

$\text{New score}=85+(0.07\times 85)$

$\text{New score}=85+5.95$

$\text{New score}=90.95$

Therefore, the new score will be 90.95%.

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Would apreciate if someone helped me..

PtichkaEL [24]

Answer:

a). x = 11

b). m∠DMC = 39°

c). m∠MAD = 66°

d). m∠ADM = 36°

e). m∠ADC = 18°

Step-by-step explanation:

a). In the figure attached,

m∠AMC = 3x + 6

and m∠DMC = 6x - 49

Since "in-center" of a triangle is a points where the bisectors of internal angles meet.

Therefore, MC is the angle bisector of angle AMD.

and m∠AMC ≅ m∠DMC

3x + 6 = 8x - 49

8x - 3x = 49 + 6

5x = 55

x = 11

b). m∠DMC = 8x - 49

= (8 × 11) - 49

= 88 - 49

= 39°

c). m∠MAD = 2(m∠DAC)

= 2(30)°

= 60°

d). Since, m∠AMD + m∠ADM + m∠MAD = 180°

2(39)° + m∠ADM + 66° = 180°

78° + m∠ADM + 66° = 180°

m∠ADM = 180° - 144°

= 36°

e). m∠ADC = $\frac{1}{2}(m\angle ADM)$

= $\frac{1}{2}(36)$

= 18°

5 0

2 years ago

Frans filing cabinet is 6 feet tall 1 1/3 feet wide and 3 feet deep. She plans to paint all sides except the bottom of the cabin

aleksley [76]

Well you are look at a 3d image here
so if area is length times width then we need to find the area of every side of the cabinet and add it up
11/3 on the calculator is 3.66666667 sooooo....
top: 3 x 11/3 = 11
side 1: 3 x 6 = 18
side 2: 3 x 6 = 18
front: 6 x 11/3 = 22
back: 6 x 11/3 = 22
so we have all of our measurements:)
now we just add them up together.
11+18+18+22+22= 91!!
so Frans would have to paint 91 square inches of that cabinet:) hope i helped

6 0

2 years ago

A team of 10 players is to be selected from a class of 6 girls and 7 boys. Match each scenario to its probability. You have to d

tankabanditka [31]

The selection of r objects out of n is done in

$C(n, r)= \frac{n!}{r!(n-r)!}$ many ways.

The total number of selections 10 that we can make from 6+7=13 students is

$C(13,10)= \frac{13!}{3!(10)!}= \frac{13*12*11*10!}{3*2*1*10!}= \frac{13*12*11}{3*2}= 286$
thus, the sample space of the experiment is 286

A.
"The probability that a randomly chosen team includes all 6 girls in the class."

total number of group of 10 which include all girls is C(7, 4), because the girls are fixed, and the remaining 4 is to be completed from the 7 boys, which can be done in C(7, 4) many ways.

 $C(7, 4)= \frac{7!}{4!3!}= \frac{7*6*5*4!}{4!*3*2*1}= \frac{7*6*5}{3*2}=35$

P(all 6 girls chosen)=35/286=0.12

B.
"The probability that a randomly chosen team has 3 girls and 7 boys."

with the same logic as in A, the number of groups were all 7 boys are in, is

 $C(6, 3)= \frac{6!}{3!3!}= \frac{6*5*4*3!}{3!3!}= \frac{6*5*4}{3*2*1}=20$

so the probability is 20/286=0.07

C.
"The probability that a randomly chosen team has either 4 or 6 boys."

case 1: the team has 4 boys and 6 girls

this was already calculated in part A, it is 0.12.

case 2, the team has 6 boys and 4 girls.

there C(7, 6)*C(6, 4) ,many ways of doing this, because any selection of the boys which can be done in C(7, 6) ways, can be combined with any selection of the girls.

 $C(7, 6)*C(6, 4)= \frac{7!}{6!1}* \frac{6!}{4!2!} =7*15= 105$

the probability is 105/286=0.367

since case 1 and case 2 are disjoint, that is either one or the other happen, then we add the probabilities:

0.12+0.367=0.487 (approximately = 0.49)

D.
"The probability that a randomly chosen team has 5 girls and 5 boys."

selecting 5 boys and 5 girls can be done in

 $C(7, 5)*C(6,5)= \frac{7!}{5!2} * \frac{6!}{5!1}=21*6=126$

many ways,

so the probability is 126/286=0.44

6 0

2 years ago

Read 2 more answers

What is the nearest ten thousand, the population of Vermont was estimated to be about 620,000 in 2008 . What might have been the

Degger [83]

Answer:

618,000 might be the exact population of Vermont in 2008

Step-by-step explanation:

* Lets explain the rule of rounding to the nearest ten thousands

- To round numbers to the nearest ten thousand, make the

numbers whose last four digits are 0001 through 4999 into the

next lower number that ends in 0000

- Ex: 83,525 rounded to the nearest ten thousand would be

80,000.

- Numbers that have the last four digits of 5000 or more should

be rounded up to the next even ten thousand

- Ex: The number 58,988 rounded to the nearest ten thousand

would be 60,000

* Lets do that in the problem

∵ The number is 620,000 after rounded to the nearest

ten thousands

∴ We can chose any number whose last four digits are 00001

through 4999 as 624,000 OR 5000 or more as 618,000

∴ 618,000 might be the exact population of Vermont in 2008

6 0

2 years ago

One side of a rectangle is 3 feet shorter than twice the other side find the sides if the area is 209 feet squared

AfilCa [17]

Answer:

29119.66666...+14561.3333...=43681, 209ft^2, not square feet.

Step-by-step explanation:

"One side of a rectangle is 3 feet shorter than twice the other side find the sides if the area is 209 feet squared"

Ok, so this is a tricky one- 209 feet squared, not 209 square feet, therefore the area is 209^2, or 43,681.

Next, let's define our variables-

x= the "other side"

z= 3 feet shorter than twice side

We can now make these (useful) equations

z=2x-3

43681= (2x-3)+x

We will focus on the latter for now-

Simplify

43681= (2x-3)+x

43681= 2x-3+x

43681= 3x-3

43684=3x

14561.3333...=x

z=2x-3

z=2*(14561.3333)-3

z=29119.66666....

29119.66666...+14561.3333...=43681

6 0

2 years ago