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Lady_Fox [76]
1 year ago
8

Qué aspectos de la formación intelectual del escritor destaca la autora ?

Mathematics
1 answer:
navik [9.2K]1 year ago
7 0

Respuesta: " ¿Quién diría que una persona que no haya culminado sus estudios universitarios pudiera hablar más de diez idiomas, y además crear un idioma universal? "

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There are 16 cats and 14 dogs in a local animal shelter. Which phrase describes a ratio relationship between the two quantities?
Tcecarenko [31]
They are comparing the number of cats in teh shelter to the number of dogs in the shelter.
6 0
2 years ago
Read 2 more answers
arleen has a gift card for a local lawn and garden store. she uses the gift card to rent a roller for 4 days. it cost $17 per da
kaheart [24]

Answer:

We use negative values for the money Arleen spends.

a) We determine the change to the value on her gift card:

4(-35)+(-9)= -140+(-9)=-149

b) We determine the amount on money she has left on the gift card after renting the tiller and buying the rake:

200+(-149)=51

Since she has got $51 on her gift card and a wheelbarrow is $50 she is able to buy it:

51>50

RESULT

a) -$149 less b) yes

Step-by-step explanation:

7 0
2 years ago
Phil has 3 times as many rocks as Peter. Together, they have 48 rocks. How many more rocks does Phil have than Peter?
Ivan
Let x = the number of marbles for Phil
Then 3x = the number of marbles for Peter
Together they have 3x+x=48 or 4x=48 and x=12
So Phil has x = 12 marbles and Peter has 3x, let x = 12, 3(12) = 36 marbles.
Peter has 24 more marbles than Phil.
3 0
2 years ago
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It is a widely held belief that a typical piece of printer paper with a thickness of 0.1 mm can go through at most 7 folds. When
Juli2301 [7.4K]
No. of layers= 2^7 = 128 layers
thickness = 128*0.1 = 12.8mm
hope it helps.
3 0
2 years ago
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The table shows some of the values of a function of the form y=ax^2+bx+c which is the value of c, the constant, the constant for
cupoosta [38]

Answer:

c=8

Step-by-step explanation:

Given: y=ax^2+bx+c

To find: c

Solution:

At x=4,y=48:

48=16a+4b+c    (i)

At x=5,y=73:

73=25a+5b+c    (ii)

At x=6,y=104:

104=36a+6b+c   (iii)

On subtracting (i) and (ii),

25=9a+b   (iv)

On subtracting (i) and (iii),

56=20a+2b\\\\28=10a+b    \,\,\,\,(v)

On subtracting (iv) and (v),

a=3

Put a=3 in (iv)

25=9(3)+b\\25=27+b\\25-27=b\\-2=b

Put a=3,b=-2 in (iii)

104=36(3)+6(-2)+c\\104=108-12+c\\104=96+c\\104-96=c\\8=c

5 0
2 years ago
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