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marin [14]
2 years ago
12

X(4-k)=p solve for k

Mathematics
2 answers:
kirill [66]2 years ago
6 0

Answer:

k=4-p\frac{p}{x}

Step-by-step explanation:

Given : Expression x(4-k)=p

To find : Solve for k?

Solution :

Step 1 - Write the expression,

x(4-k)=p

Step 2 - Divide by x both side,

\frac{x(4-k)}{x}=\frac{p}{x}

4-k=p\frac{p}{x}

Step 3 - Taking k to one side,

k=4-p\frac{p}{x}

Therefore, k=4-p\frac{p}{x}

den301095 [7]2 years ago
4 0
<span> x(4-k)=p
[x(4-k)=p]/x

4-k=p/x
-4 = -4
-k=p/x-4
k=4-p/x
</span>
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The scale factor described denotes a reduction operation. The missing dimension is given by simple rule of three:

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3 0
2 years ago
On a certain​ route, an airline carries 7000 passengers per​ month, each paying ​$30. A market survey indicates that for each​ $
KengaRu [80]

Answer:

The ticket price that maximizes revenue is $50.

The maximum monthly revenue is $250,000.

Step-by-step explanation:

We have to write a function that describes the revenue of the airline.

We know one point of this function: when the price is $30, the amount of passengers is 7000.

We also know that for an increase of $1 in the ticket price, the amount of passengers will decrease by 100.

Then, we can write the revenue as the multiplication of price and passengers:

R=p\cdot N=(30+x)(7000-x)

where x is the variation in the price of the ticket.

Then, if we derive R in function of x, and equal to 0, we will have the value of x that maximizes the revenue.

R(x)=(30+x)(7000-100x)=30\cdot7000-30\cdot100x+7000x-100x^2\\\\R(x)=-100x^2+(7000-3000)x+210000\\\\R(x)=-100x^2+4000x+210000\\\\\\\dfrac{dR}{dx}=100(-2x)+4000=0\\\\\\200x=4000\\\\x=4000/200=20

We know that the increment in price (from the $30 level) that maximizes the revenue is $20, so the price should be:

p=30+x=30+20=50

The maximum monthly revenue is:

R(x)=(30+x)(7000-100x)\\\\R(20)=(30+20)(7000-100\cdot20)\\\\R(20)=50\cdot5000\\\\R(20)=250000

3 0
2 years ago
The water under a draw bridge was 15 feet deep at midnight. As the tide went out, the
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Answer:

80 minutes or 1 h 20 minutes

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Total number of shares is to increase by 12.8%

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8 0
2 years ago
I am a multiple of 60 I am between 400 and 600 I am 40 away from a multiple of 100 who am I
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