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ipn [44]
2 years ago
12

Ian has 12.2 ounce bottle of ketchip. He uses 1/20 of the ketchup every time he has a buffalo burger How many ounces of ketchup

are left after Ian has eaten 4 buffalo burgers?
Mathematics
1 answer:
tatiyna2 years ago
4 0
If Ian uses 1/20 of the ketchup 4 times, this is equal to 4/20, or \frac{4}{20}.

\frac{4}{20} can be simplified to \frac{1}{5}, which means we need to work out \frac{1}{5} of 12.2

\frac{1}{5} is equivalent to 20%, which as a decimal is 0.2

0.2 x 12.2 = 2.44 - however, this is how much he has used, and we need to figure out how much is left.

12.2 - 2.44 = 9.76

So, Ian has 9.76 oz remaining :)

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erma4kov [3.2K]

Answer:

Step-by-step explanation:

given are four statements and we have to find whether true or false.

.1 If two matrices are equivalent, then one can be transformed into the other with a sequence of elementary row operations.

True  

2.Different sequences of row operations can lead to different echelon forms for the same matrix.

True in whatever way we do the reduced form would be equivalent matrices

3.Different sequences of row operations can lead to different reduced echelon forms for the same matrix.

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8 0
1 year ago
The commission Gary earns is proportional to the cost of the shoes he sells. Gary earns 15% in commission for every $150 worth o
barxatty [35]
C = $150x * .15 is the formula
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2 years ago
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10x - 77 =7y <br> solve for y
lutik1710 [3]
You have to get y by itself. Divide by 7 on both sides to get 1.43x-11=y. Hope this helps! ;)
5 0
2 years ago
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Lera brought a watermelon that weighed b kg to a party. Nick brought a box of candies. How much is the weight of the box of cand
Dennis_Churaev [7]

Answer:

1.5b (kg)

Step-by-step explanation:

Let's begin by listing out the variables we were given:

weight of the watermelon = b (kg),

weight of watermelon = (2/5) * weight of candies

weight of candies = 1 ÷ (2/5) = 1 ÷ 0.4

weight of candies = 2.5b (kg)

How much is the weight of the box of candies greater than the weight of the watermelon is given by:

weight of the box of candies - weight of watermelon= 2.5b - b = <u>1.5b</u> (kg)

<u>Therefore, the weight of the box of candies is greater than the weight of the watermelon by 1.5b (kg) </u>

7 0
2 years ago
A university warehouse has received a shipment of 25 printers, of which 10 are laser printers and 15 are inkjet models. If 6 of
Tanya [424]

Answer:

The probability is 0.31

Step-by-step explanation:

To find the probability, we will consider the following approach. Given a particular outcome, and considering that each outcome is equally likely, we can calculate the probability by simply counting the number of ways we get the desired outcome and divide it by the total number of outcomes.

In this case, the event of interest is  choosing 3 laser printers and 3 inkjets. At first, we have a total of 25 printers and we will be choosing 6 printers at random. The total number of ways in which we can choose 6 elements out of 25 is \binom{25}{6}, where \binom{n}{k} = \frac{n!}{(n-k)!k!}. We have that \binom{25}{6} = 177100

Now, we will calculate the number of ways to which we obtain the desired event. We will be choosing 3 laser printers and 3 inkjets. So the total number of ways this can happen is the multiplication of the number of ways we can choose 3 printers out of 10 (for the laser printers) times the number of ways of choosing 3 printers out of 15 (for the inkjets). So, in this case, the event can be obtained in \binom{10}{3}\cdot \binom{15}{3} = 54600

So the probability of having 3 laser printers and 3 inkjets is given by

\frac{54600}{177100} = \frac{78}{253} = 0.31

4 0
2 years ago
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