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madam [21]
2 years ago
7

Lera brought a watermelon that weighed b kg to a party. Nick brought a box of candies. How much is the weight of the box of cand

ies greater than the weight of the watermelon if the weight of the watermelon is 2/5 of the weight of the box of candies?
Mathematics
1 answer:
Dennis_Churaev [7]2 years ago
7 0

Answer:

1.5b (kg)

Step-by-step explanation:

Let's begin by listing out the variables we were given:

weight of the watermelon = b (kg),

weight of watermelon = (2/5) * weight of candies

weight of candies = 1 ÷ (2/5) = 1 ÷ 0.4

weight of candies = 2.5b (kg)

How much is the weight of the box of candies greater than the weight of the watermelon is given by:

weight of the box of candies - weight of watermelon= 2.5b - b = <u>1.5b</u> (kg)

<u>Therefore, the weight of the box of candies is greater than the weight of the watermelon by 1.5b (kg) </u>

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Answer :

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2 years ago
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Answer:

6 and 18 are common because 6x3=18. Remember the rule to multiply all numbers by 3. So multiply 10 by 3 and you will get 30. The total number of square tiles needed is 30 tiles. If you are putting it into a ratio it would be 18:30.

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In a right triangle, angle A measures 20°. The side opposite angle A is 10 centimeters long. Approximately how long is the hypot
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The equation of a circle is (x + 12)2 + (y + 16)2 = (r1)2, and the circle passes through the origin. The equation of the circle
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For an equation to pass through the origin, (0,0) must be a solution of the equation. So, for the first one, 

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(0, 0) must satisfy the equation and we can solve for the value of r₁ as shown below.

(0 + 12)^{2} + (0 + 16)^{2} = r_{1}^{2}
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Answer: r₁ = 20 and r₂ = 34
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