Answer:
Option B
Step-by-step explanation:
From the figure attached,
Circle D is drawn with the radius = DG or DE
A tangent FG has been drawn at a point G on the circle from an external point F.
By theorem,
Radius of a circle is always perpendicular to the tangent, drawn to the circle from an external point.
Therefore, DG ⊥ FG.
Option B will be the correct option.
A decagon has 10 sides.
It it is regular you can build 10 isosceles triangles from the center of the decagon to the 10 sides.
Each triangle has a common vertex where the angle of each triangle is 360° / 10 = 36°.
So each time that you rotate the decagon a multiple of 36° around the center you get an image that coincides with the original decagon.
If the letters are given clockwise:
- when you rotate 36° counter clockwise, the point A' (the image of A) will coincide with the point J.
- when you rotate 72° (2 times 36°) counter clockwise, the point A' will land on I.
- when you rotate 108° (3 times 36°) counter clockwise, the point A' will land on H.
- when you rotate 144° (4 times 36°) counter clockwise, the point A' will land on G.
- when you rotate 180° (5 times 36°) counter clockwise, the point A' will land on I.
- when you rotate 216° (6 times 36°) counter clockwise, the point A' will land on E.
- whn you rotate 252° (7 times 36°) counterclockwise, the point A' will coincide with D.
Add other 36° each time and A' will coincide successively with C, B and the same A.
Its depends on how many times you score during the game
in second game the number of points increases as a geometric sequence
with common ratio 2
so for example if you score ten times in first game you get 2000 points
if you score 10 times in Game 2 you score 2 * (2^10) - 1 = 2046 points
so playing 10 or more games is best with Game 2. Any less plays favours gane 1.
If you would like to find the matching equation, you can do this using the following steps:
ax^2 + bx + c = 0
a = -2
b = 1
c = 3
-2x^2 + x + 3 = 0
The correct result would be a. 0 = <span>-2x^2 + x + 3.</span>
