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aniked [119]
2 years ago
8

-3(2t - 1) = t + t + t + 3

Mathematics
2 answers:
densk [106]2 years ago
5 0

Answer:

-3(2t - 1) = t + t + t + 3

-6t + 3 = 3t + 3

-6t -3t = 3t - 3t +3

-9t + 3 - 3 = 0

9t = 0

t = 0

Step-by-step explanation:

Allisa [31]2 years ago
4 0
T = 0

isolate the variable
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A firkin is an old British unit of volume equal to 9 gallons. How many cubic meters are there in 6.00 firkins?
Rainbow [258]

Answer:

0.245489 cubic meters.

Step-by-step explanation:

It is given that a firkin is an old British unit of volume equal to 9 gallons.

1 firkin = 9 gallons

6 firkins = 54 gallons

We need convert 6.00 firkins to cubic meters.

We know that,

1 gallon = 0.00454609 cubic meters

54 gallon = 0.24548886 cubic meters

6 firkins = 0.245489 cubic meters.

Therefore, 6.00 firkins is equivalent to 0.245489 cubic meters.

7 0
2 years ago
. The cost of 2 pizzas and 1 burger is ₹ 450. Write a linear equation for this situation and draw its graph.​
Akimi4 [234]

Answer:

The linear equation is;

Y = 450 - 2·X

Please find the included graph

Step-by-step explanation:

Whereby we have the following relation;

The cost of 1 pizza = X

The cost of 1 burger = Y

Hence;

450 = Y + 2·X

Which gives;

Y = 450 - 2·X

The linear equation for the situation is therefore as presented above

The graph of the linear equation can be plotted using the assumed data as follows;

Y,           X

1,           448

2,          446

3,         444

4,          442

5,          440

6,          438

7,          436

8,          434

9,          432

10,          430

11,          428

12,          426

13,          424

14,          422

15,          420

16,            418

8 0
2 years ago
Tasha invests in an account that pays 1.5% compound interest annually. She uses the expression P(1+r)t to find the total value o
zhenek [66]
\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$3000\\
r=rate\to 1.5\%\to \frac{1.5}{100}\to &0.015\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &5
\end{cases}
\\\\\\
A=3000\left(1+\frac{0.015}{1}\right)^{1\cdot 5}\implies A=3000(1.015)^5\implies A\approx 3231.852
5 0
2 years ago
Read 2 more answers
An English professor assigns letter grades on a test according to the following scheme. A: Top 7% of scores B: Scores below the
Assoli18 [71]
The limits for a C grade are 68 to 78.

4 0
2 years ago
How to solve q =r/2(s+t) for t
Lera25 [3.4K]
<span>q =r/2(s+t) for t
</span><span>2q =r(s+t) 
2q = rs + rt
rt = 2q - rs
 t = 2q/r - s
hope it helps</span>
4 0
2 years ago
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