Answer:
- 5.8206 cm
- 10.528 cm
- 23.056 cm^2
Step-by-step explanation:
(a) The Law of Sines can be used to find BD.
BD/sin(48°) = BD/sin(50°)
BD = (6 cm)(sin(48°)/sin(60°)) ≈ 5.82064 cm
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(b) We can use the Law of Cosines to find AD.
AD^2 = AB^2 +BD^2 -2·AB·BD·cos(98°) . . . . . angle ABD = 48°+50°
AD^2 ≈ 110.841
AD ≈ √110.841 ≈ 10.5281 . . . cm
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(c) The area of ∆ABD can be found using the formula ...
A = ab·sin(θ)/2 . . . . . where a=AB, b=BD, θ = 98°
A = (8 cm)(5.82064 cm)sin(98°)/2 ≈ 23.0560 cm^2
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Angle ABD is the external angle of ∆BCD that is the sum of the remote interior angles BCD and BDC. Hence ∠ABD = 48° +50° = 98°.
Answer:
(a) 0.932
(b) 0.0653
(c) 0.032
(d) 0.316
(e) 0.251
Step-by-step explanation:
From the table with mean parameter μ = 5, we can compute the following cumulative and density probability
(a) 
(cumulative)
(b) P(X = 8) = 0.0653 (density)
(c) 
(cumulative)
(d) 
(cumulative)
(e) 
Let's say x is J because it's Lemon Juice.
It's said that the pH of J is less than 4 so: pH(J) < 4 and pH(J) is greater than 1.5 so: pH(J) > 1.5
Now we can construct:
Or simply:
We can also write this with an interval:
Hope this helps.
r3t40
Denise is constructing A square.
Note: A square has all sides equal.
We already given two vertices M and N of the square.
And another edge of the square is made by from N.
Because a square has all sides of equal length, the side NO should also be equal to MN side of the square.
Therefore, <em>Denise need to place the point of the compass on point N and draw an arc that intersects N O, using MN as the width for the opening of the compass. That would make the NO equals MN.</em>
Therefore, correct option is :
D) place the point of the compass on point N and draw an arc that intersects N O, using MN as the width for the opening of the compass.
Answer:1: Row 3
2: Row 2
3:6 and 10
Step-by-step explanation:
I just finished doing the assignment
