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Blababa [14]
1 year ago
13

A toy store owner gives 47 balloons to his customers. He has 7 balloons left. How many balloons did he start with?

Mathematics
1 answer:
Mademuasel [1]1 year ago
6 0

Answer:


Step-by-step explanation:


As per the problem, we are given that

Toy store owner gave 47 balloons to his customers.

And there are 7 balloons left.

So we can find the total number of balloons the Toy store owner start with by adding the given numbers.

Hence total number of balloons the Toy store owner start with=47+7=54

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Ben used 325 centimeters of ribbon to trim banners he made. How many meters of ribbon did he use?
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Answer:

the answer would be 3.25 meters

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bob is having a party and want to order some cake. there will be 57 guest and he wants to make sure that everyone gets a slice o
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<span>Bob should by the 25cm cake for 18.75 each. He will need to buy 3 of these cakes in order to feed 57 guests. The total cost would be 56.25. If he were to buy the 20cm cake, he would need to purchase 5 cakes for a total of 67.50.</span>
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2 years ago
On Friday, Kelsey went to a local carnival. She bought a pretzel for $5 and played three games. On Saturday, Kelsey went back to
lara31 [8.8K]
Set the question up as an equation, where x is equal to the cost of a game
FRIDAY: 5+3x
SATURDAY: 3+5x

∴ 5+3x=3+5x
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   x=1
Therefore the cost of 1 game is $1

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If on a scale drawing 15 feet are represented by 10 inches then a scale of 1/10 inch represents how many feet
GenaCL600 [577]

A scale of \frac{1}{10} inches will represent \frac{3}{20} feet.

Step-by-step explanation:

According to scale drawing;

15 feet = 10 inches

1 inch = \frac{15}{10}=\frac{3}{2}\ feet

A scale of \frac{1}{10} inch will represent;

Multiplying both sides by

\frac{1}{10}*1=\frac{3}{2}*\frac{1}{10}\\\\\frac{1}{10}\ inches = \frac{3}{20}\ feet

A scale of \frac{1}{10} inches will represent \frac{3}{20} feet.

Keywords: fraction, multiplication

Learn more about fractions at:

  • brainly.com/question/4054269
  • brainly.com/question/4163549

#LearnwithBrainly

3 0
2 years ago
There are 345 students at a college who have taken a course in calculus, 212 who have taken a course in discrete mathematics, an
ollegr [7]

Answer:

369 students have taken a course in either calculus or discrete mathematics

Step-by-step explanation:

I am going to build the Venn's diagram of these values.

I am going to say that:

A is the number of students who have taken a course in calculus.

B is the number of students who have taken a course in discrete mathematics.

We have that:

A = a + (A \cap B)

In which a is the number of students who have taken a course in calculus but not in discrete mathematics and A \cap B is the number of students who have taken a course in both calculus and discrete mathematics.

By the same logic, we have that:

B = b + (A \cap B)

188 who have taken courses in both calculus and discrete mathematics.

This means that A \cap B = 188

212 who have taken a course in discrete mathematics

This means that B = 212

345 students at a college who have taken a course in calculus

This means that A = 345

How many students have taken a course in either calculus or discrete mathematics

(A \cup B) = A + B - (A \cap B) = 345 + 212 - 188 = 369

369 students have taken a course in either calculus or discrete mathematics

4 0
2 years ago
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