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Dima020 [189]
2 years ago
12

Triangle PQR is dilated by a scale factor of 1.5 to form triangle P′Q′R′. This triangle is then dilated by a scale factor of 2 t

o form triangle P″Q″R″. If vertex P is at (3, -4) and vertex Q is at (5, -1), what are the coordinates of vertices P″ and Q″?
P″(4.5, -6) and Q″(7.5, 1.5)
P″(4.5, -6) and Q″(7.5, -1.5)
P″(-9, 12) and Q″(15, -3)
P″(9, -12) and Q″(15, -3)
P"(-9, -12) and Q"(-15, -3)
Mathematics
2 answers:
statuscvo [17]2 years ago
5 0

Answer: P″(9, -12) and Q″(15, -3)

Step-by-step explanation:

When a figure with coordinate (x,y) dilated by scale factor k , then the coordinates of the image is given by :-

(x,y)\to(kx,ky)

Given : The coordinates of vertex P is (3, -4) and Q is (5, -1) .

Triangle PQR is dilated by a scale factor of 1.5 to form triangle P′Q′R′.

Then, the co-ordinates of P' and Q' are given by:-

P(3,-4)\to P'(1.5\cdot3,\ 1.5\cdot-4)=P'(4.5,\ -6)

Q(5,-1)\to Q'(1.5\cdot5,\ 1.5\cdot-1)=P'(7.5,\ -1.5)

Triangle P′Q′R′ is then dilated by a scale factor of 2 to form triangle P″Q″R″.

Then, the co-ordinates of P" and Q" are given by:-

P"(4.5,\ -6)\to P"(2\cdot4.5,\ 2\cdot-6)=P"(9,\ -12)

Q'(7.5,\ -1.5)\to Q'(2\cdot7.5,\ 2\cdot-1.5)=P'(15,\ -3)

Hence, the coordinates of vertices P″ and Q″ are P″(9, -12) and Q″(15, -3).

Ghella [55]2 years ago
4 0

Answer:  The correct option is (D) P″(9, -12) and Q″(15, -3).

Step-by-step explanation:  Given that triangle PQR is dilated by a scale factor of 1.5 to form triangle P′Q′R′. This triangle is then dilated by a scale factor of 2 to form triangle P″Q″R″.

The co-ordinates of vertices P and Q are (3, -4) and (5, -1) respectively.

We are to find the co-ordinates of the vertices P″ and Q″.

<u>Case I :</u>  ΔPQR dilated to ΔP'Q'R'

The co-ordinates of P' and Q' are given by

P'(3\times 1.5, -4\times 1.5)=P'(4.5, -6),\\\\Q'(5\times 1.5, -1\times 1.5)=Q'(7.5, -1.5).

<u>Case II :</u>  ΔP'Q'R' dilated to ΔP''Q''R''

The co-ordinates of P'' and Q'' are given by

P''(4.5\times 2, -6\times 2)=P'(9, -12),\\\\Q'(7.5\times 2, -1.5\times 2)=Q'(15, -3).

Thus, the co-ordinates of the vertices P'' and Q'' are (9, -12) and (15, -3).

Option (D) is CORRECT.

<u></u>

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So we are eliminating 3rd choice now.

Let's look at the fourth choice.

\csc(\frac{7\pi}{6})=-2 \text{ since } \sin(\frac{7\pi}{6})=\frac{-1}{2} which means \csc(\frac{7\pi}{6}) and not greater than 1.

I was looking at the rows as if they were choices.

Let me break up my choices.

So we said x=-\frac{7\pi}{6} doesn't work because it is not included in the inequality 0\le x \le 2\pi.

How about x=0?  This leads to \csc(0) which doesn't exist because \sin(0)=0.

So neither of the first two choices on the first row.

Let's look at the second row again.

We said \frac{\pi}{4} worked but not \frac{\pi}{2}

Let's look at the choices on the third row.

We said \frac{5\pi}{6} worked but not x=\pi

Let's look at at the last choice.

We said it gave something less than 1 so this choice doesn't work.

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