All categories

2 years ago

How many terms are present in the expression (2 + 5 + 8)? A). 1. B). 2. C). 3. D). 15.

2 answers:

4 0

In this specific problem each term is separated by an addition sign , so you have a total of 3 terms . The correct answer is " C."<span />

lubasha [3.4K]2 years ago

3 0

Answer:

i think it is 3 terms so the anser is C.

Step-by-step explanation:

You might be interested in

Apply the distributive property to factor out the greatest common factor 16g+20h

UkoKoshka [18]

Answer:

4(4g+5h)

Step-by-step explanation:

Factor out the 4.

5 0

2 years ago

Choose the correct simplification of (3x3 + 2x2 − 5x) − (8x3 − 2x2)

zmey [24]

(3x³ + 2x² - 5x) - (8x³ - 2x²<span>) =
</span>3x³ + 2x² - 5x - 8x³ + 2x² =
-5x³ + 4x² - 5x

5 0

2 years ago

Read 2 more answers

Given: ΔABC, AC = BC, AB = 3 CD⊥ AB, CD = 3 Find: AC

viva [34]

Answer:

3 $\sqrt{5}$ /2

Step-by-step explanation:

As given, AC = BC, its an isosceles triangle.

Now, CD is perpendicular to AB, therefore AD = DB = 0.5AB = 3/2

Now take triangle ACD,

using Pythagoras theorem,

AC = $\sqrt{AD^{2} + CD^{2} }$

AC = 3 $\sqrt{5}$ /2

:-)

4 0

2 years ago

Read 2 more answers

G find the area of the surface over the given region. use a computer algebra system to verify your results. the sphere r(u,v) =

Svetach [21]

Presumably you should be doing this using calculus methods, namely computing the surface integral along $\mathbf r(u,v)$ .

But since $\mathbf r(u,v)$ describes a sphere, we can simply recall that the surface area of a sphere of radius $a$ is $4\pi a^2$ .

In calculus terms, we would first find an expression for the surface element, which is given by

$\displaystyle\iint_S\mathrm dS=\iint_S\left\|\frac{\partial\mathbf r}{\partial u}\times\frac{\partial\mathbf r}{\partial v}\right\|\,\mathrm du\,\mathrm dv$

$\dfrac{\partial\mathbf r}{\partial u}=a\cos u\cos v\,\mathbf i+a\cos u\sin v\,\mathbf j-a\sin u\,\mathbf k$
$\dfrac{\partial\mathbf r}{\partial v}=-a\sin u\sin v\,\mathbf i+a\sin u\cos v\,\mathbf j$
$\implies\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}=a^2\sin^2u\cos v\,\mathbf i+a^2\sin^2u\sin v\,\mathbf j+a^2\sin u\cos u\,\mathbf k$
$\implies\left\|\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}\right\|=a^2\sin u$

So the area of the surface is

$\displaystyle\iint_S\mathrm dS=\int_{u=0}^{u=\pi}\int_{v=0}^{v=2\pi}a^2\sin u\,\mathrm dv\,\mathrm du=2\pi a^2\int_{u=0}^{u=\pi}\sin u$
$=-2\pi a^2(\cos\pi-\cos 0)$
$=-2\pi a^2(-1-1)$
$=4\pi a^2$

as expected.

6 0

2 years ago

The Rockville Employment Agency just placed Howard Jacobson in a job as a junior pharmacist. The job pays $51.2k. The agency fee

yan [13]

His annual salary as a pharmacist is $51,200

There are a total of 52 weeks in an year.

(a) Weekly salary = annual salary/ number of weeks = 51,200/52 = $984.62 (rounded to the nearest cent)

Howard's weekly salary to the nearest cent = $984.62

(b) His salary in first three weeks = 984.62*3 = $2,953.85

Howard's earnings during the first three weeks to the nearest cent = $2,953.85

Howard must pay to the employment agency to the nearest dollar = $1,182

6 0

2 years ago