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krek1111 [17]
2 years ago
5

How many terms are present in the expression (2 + 5 + 8)? A). 1. B). 2. C). 3. D). 15.

Mathematics
2 answers:
Arlecino [84]2 years ago
4 0
In this specific problem each term is separated by an addition sign , so you have a total of 3 terms . The correct answer is " C."<span />
lubasha [3.4K]2 years ago
3 0

Answer:

i think it is 3 terms so the anser is C.

Step-by-step explanation:


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on a sunny day liam decided to walk to his grandmother's house. After walking for a while at a rate of 3 mph, Liam realized that
inna [77]

Answer:

the answer is 10

Step-by-step explanation:

7 0
1 year ago
4. A bank vault has 3 locks with a key for each lock. Key A is owned by the bank manager. Key B is owned by the senior bank tell
Amanda [17]

1 means that he is present, 0 means that he is not.

True means that they can open.

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6 0
2 years ago
A random draw is being designed for 210 participants. A single winner is to be chosen, and all the participants must have an equ
Over [174]

Answer: The correct number of balls is (b) 4.

Step-by-step explanation:  Given that a single winner is to be chosen in a random draw designed for 210 participants. Also, there is an equal probability of winning for each participant.

We are using 10 balls, numbered through 0 to 9. We are to find the number of balls which needs to be picked up, regardless of order, so that each of the 210 participants can be assigned a unique set of numbers.

Let 'r' represents the number of balls to be picked up.

Since we are choosing from 10 balls, so we must have

^{10}C_r=210.

The value of 'r' can be any one of 0, 1, 2, . . , 10.

Now,

if r = 1, then

^{10}C_1=\dfrac{10!}{1!(10-1)!}=\dfrac{10!}{1!9!}=\dfrac{10\times 9!}{1\times 9!}=10

If r = 2, then

^{10}C_2=\dfrac{10!}{2!(10-2)!}=\dfrac{10!}{2!8!}=\dfrac{10\times 9\times 8!}{2\times 1\times 8!}=45

If r = 3, then

^{10}C_3=\dfrac{10!}{3!(10-3)!}=\dfrac{10!}{3!7!}=\dfrac{10\times 9\times 8\times 7!}{3\times 2\times 1\times 7!}=120

If r = 4, then

^{10}C_4=\dfrac{10!}{4!(10-4)!}=\dfrac{10!}{4!6!}=\dfrac{10\times 9\times 8\times\times 7\times 6!}{4\times 3\times 2\times 1\times 6!}=210.

Therefore, we need to pick 4 balls so that each participant can be assigned a unique set of numbers.

Thus, (b) is the correct option.

4 0
2 years ago
Read 2 more answers
Ben and Joel are raising money for their class trip by selling wrapping paper. Ben raised $43.50 by selling 12 rolls of solid pa
xz_007 [3.2K]

Step-by-step explanation:

Solid paper costs 1.75 each

Printed paper costs 2.50 each

Given:

Ben = $43.50 (12 rolls solid paper and 9 rolls of printed paper)

Joel = $51.50 (8 rolls solid paper and 15 rolls of printed paper)

Let x = solid paper

Let y = printed paper

12x + 9y = 43.50

 8x + 15y = 51.50

Find x:

8x + 15y = 51.50

8x = 51.50 - 15y

x = (51.50 - 15y)/8

Substitute x:

12x + 9y = 43.50

12(51.50 - 15y)/8 + 9y = 43.50

(618 - 180y)/8 + 9y = 43.50

8 (618 - 180y)/8 + 8*9y = 43.50 * 8

618 - 180y + 72y = 348

-108y = 348 - 618

-108y = -270

-108y/-108 = -270/-108

y = 2.50

x = (51.50 - 15y)/8

x = (51.50 - 15(2.5) /8

x = (51.50 - 37.50)/8

x = 14/8

x = 1.75

To check: x = 1.75 ; y = 2.5

12x + 9y = 43.50

12(1.75) + 9(2.5) = 43.50

21 + 22.50 = 43.50

43.50 = 43.50

8x + 15y = 51.50

8(1.75) + 15(2.5) = 51.50

14 + 37.50 = 51.50

51.50 = 51.50

6 0
2 years ago
Lupe can ride her bike at a rate of 20 mph when there is no wind. On one particular day, she rode 2 miles against the wind and n
miskamm [114]
Time = 3 miles / (20 mph - wind velocity)
time = 2 miles / (20 mph + wind velocity)

3 miles / (20 mph + wind velocity) = 2 miles / (20 mph - wind velocity)

3/2 =  (20 mph + wind velocity) / (20 mph - wind velocity)

1.5 =  (20 mph + wv) / (20 mph -wv)

30 mph -1.5wv = 20 mph -wv

10 mph = 2.5 wv

wind velocity = 4 mph


3 0
2 years ago
Read 2 more answers
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