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Sonja [21]
1 year ago
15

Select all the ways the rectangle could have been rotated to get from Frame 1 to Frame 2. 40 degrees clockwise 40 degrees counte

rclockwise 90 degrees clockwise 90 degrees counterclockwise 140 degrees clockwise 140 degrees counterclockwise Lesson 3
Mathematics
1 answer:
Klio2033 [76]1 year ago
8 0

Answer:

40 degrees clockwise

140 degrees counterclockwise

Step-by-step explanation:

The rectangle is rotated in Figure B. The angle of rotation is 40 degrees. If we rotate a rectangle at an angle of 40 degrees clockwise then wit will be at the position as shown in figure B. The 90 degrees angle is perpendicular angle. Rectangle will not reach the desired position. If we rotate the rectangle at 140 degrees counterclockwise this will be the figure B representation. The rotation to 90 degree counterclockwise is either not suitable for the desired rectangle position.

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Which of the following equations are equivalent to -2m - 5m - 8 = 3 + (-7) + m?
kondaur [170]
-2m -5m-8=3+(-7)+m equals -1/2 so 2, 4, 5 all apply
6 0
1 year ago
Pls help ASAP!!!!!!
Marrrta [24]

{6x}^{3}  - 4x {}^{2}  + 4x - 8

answer is

6x {}^{2}  + 8x +  \frac{52}{a =  - 2}

8 0
1 year ago
Un globo busca aterrizar en medio de dos ciudades A y B, cuya distancia entre si es de 200 km. Si se mide el ángulo de elevación
scoundrel [369]

Answer:

h \approx 59.898\,km

Step-by-step explanation:

El diagrama trigonométrico que representa el enunciado es incluido abajo como adjunto. Las siguientes relaciones trigonométricas describen la localización del globo. (The trigonometric diagram representing the statement is included below as attachment. The following trigonometric relations describes the location of the balloon):

\tan 27^{\circ} = \frac{h}{x}

\tan 36^{\circ} = \frac{h}{200-x}

A continuación, se obtiene la distancia horizontal: (The horizontal distance is obtained hereafter):

x \cdot \tan 27^{\circ} = (200-x)\cdot \tan 36^{\circ}

x \cdot (\tan 27^{\circ} + \tan 36^{\circ})= 200\cdot \tan 36^{\circ}

x = \frac{200\cdot \tan 36^{\circ}}{\tan 27^{\circ}+ \tan 36^{\circ}}

x \approx 117.557\,km

La altura aproximada del globo es (The approximated height of the globe is):

h = x\cdot \tan 27^{\circ}

h \approx 59.898\,km

7 0
2 years ago
Nevin made tables of values to approximate the solution to a system of equations. First he found that the x-value of the solutio
prisoha [69]

Answer:

The correct option is B.

Step-by-step explanation:

The given equation are

y=4x-3

y=-5x+9

On solving both the equation, we get

4x-3=-5x+9

4x+5x=9+3

9x=12

9x=\frac{12}{9}=\frac{4}{3}

Put this value in the given equation.

y=4(\frac{4}{3})-3

y=\frac{16}{3}-3

y=\frac{16-9}{3}

y=\frac{7}{3}

The solution of the given system of equation is

(\frac{4}{3},\frac{7}{3})=(1.333,2.333)\approx (1.3,2.3)

The best approximation of the exact solution is (1.3,2.3). Therefore the correct option is B.

7 0
2 years ago
Read 2 more answers
If the shaded cross sections of the solids have the same area, which of the following corresponds to the value of a: the side le
Nikolay [14]

Answer:

4\sqrt{\pi}

Step-by-step explanation:

  • The cross section of a sphere is a circle with area  \pi r^2, where radius is given as 4
  • The cross section of the cube is a square with area  a^2, where a is side length of square

The circle area = the square area. Thus we have:

\pi r^2 = a^2 \\\pi(4)^2=a^2\\16\pi=a^2\\\sqrt{16\pi}=a\\ a=\sqrt{16} \sqrt{\pi} \\a=4\sqrt{\pi}

6 0
2 years ago
Read 2 more answers
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