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2 years ago

Consider this equation: –2x – 4 + 5x = 8 Generate a plan to solve for the variable. Describe the steps that will be used.

2 answers:

8 0

Sample Response: The goal is to get x all alone. First combine like terms. Apply the addition property of equality to add 4 to both sides. Apply the division property of equality to divide both sides by 3. The result will be x = 4. Finally, check the solution by substituting 4 into the original equation.

horrorfan [7]2 years ago

6 0

We are given the function <span>–2x – 4 + 5x = 8 and is asked in the problem to solve for the variable x in the function. In this case, we can first group the like terms and put them in their corresponding sides:

-2x + 5x =8+4
Then, do the necessary operations.

3x = 12
x = 4.
The variable x has a value of 4.</span>

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Answer:

Step-by-step explanation:

I believe 9 miles 15x3= 45 gallons what the car holds but he gets 18 mpg

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2 years ago

What is the factored form of the polynomial 27x2y – 43xy2?

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2 years ago

Read 2 more answers

Aeen is drinking a beverage that has a pH of 3.3. Marien is drinking a beverage that has a pH of 2.7. About how many time the hy

AlekseyPX

The pH value of a solution is a logarithmic function of the hydronium ion concentration in the solution. Since we are given the pH foe both we can easily calculate the H+ ion concentration as follows:

Aeen
3.3 = -log (H+)
H+ = 0.04 M

Marien
2.7 = - log (H+)
(H+) = 0.07 M

Therefore, Aeen's drink is 0.07/0.04 or 2 times more hydrogen ion concentration than Marien's drink.

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1 year ago

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An open-top rectangular box is being constructed to hold a volume of 150 in3. The base of the box is made from a material costin

Oksanka [162]

Answer:

minimum cost of construction box are x = x = 3.4199 in and y = 10.2598 in and z = 4.2750 in

Step-by-step explanation:

given data

volume = 150 in³

base material costing = 5 cents/in²

front cost = 10 cents/in²

remainder sides cost = 2 cents/in²

to find out

the dimensions that will minimize the cost

solution

we consider here length = x and breadth = y and height = z

and

area of base = xy

area of front = xz

and area of remaining side = xz + 2yz .....................1

cost of base will be = 5xy

cost of front = 10xz

cost of remaining side = 2 ( xz+ 2yz)

and

total cost will be

total cost TC = 5xy + 10xz + 2 ( xz+ 2yz)

total cost TC = 5xy + 10xz + 2xz+ 4yz

total cost TC = 5xy + 12xz + 4yz ....................2

and total volume will be = xyz

150 = xyz

z = $\frac{150}{xy}$ .......................3

now put z value in equation 2

total cost TC = 5xy + 12xz + 4yz

total cost TC = 5xy + 12x $\frac{150}{xy}$ + 4y $\frac{150}{xy}$

total cost TC = 5xy + $\frac{1800}{y}$ + $\frac{600}{x}$ ...........4

now differentiate TC w.r.t x and y

TC (x) = 5y - $\frac{600}{x^2}$

TC (x) = 5x - $\frac{1800}{y^2}$

now equating with 0 these

5y - $\frac{600}{x^2}$ = 0

x² = $\frac{120}{y}$

and

5x - $\frac{1800}{y^2}$ = 0

x = $\frac{360}{y^2}$

solve we get

y = 10.2598

x = 3.4199

now put x and y value in equation 3

z = $\frac{150}{xy}$

z = $\frac{150}{3.4199*10.2598}$

z = 4.2750

so minimum cost of construction box are x = x = 3.4199 in and y = 10.2598 in and z = 4.2750 in

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2 years ago