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Sav [38]
2 years ago
12

a phone plan has a limit of $25 that can be spent on text messages. the base cost of the text plan will cost a user $5. each tex

t will cost $0.05. how many text messages can a user send without exceeding the plan limits
Mathematics
2 answers:
makvit [3.9K]2 years ago
8 0

0.05x + 5 = y

0.05x + 5 ≤ 25

<u>           - 5 </u>  <u> - 5 </u>

0.05x      ≤ 20

\frac{0.05}{0.05}x ≤ \frac{20}{0.05}

        x ≤ 400

Answer: 400 text messages

Keith_Richards [23]2 years ago
6 0

25 - 5 = 20
20 is after the base cost
400 \times .05 = 20.00
400 text messages can be sent without exceeding the limit.
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katovenus [111]

We are given dimensions of rectangular bedroom = length of 5m and width 3 m.

Also scale drawing of factor 1/50 of the original dimension.

In order to find the dimensions of scale drawing, we need to multiply scale factor by each dimension.

Therefore, length of the scale drawing is 5 * 1/50 = 1/10 m and

Let us convert it in centimeter now.

1 m = 100 cm

1/10 m = 100 * 1/10 = 10cm.

Width of the scale drawing = 3 * 1/50 = 3/50 m.

100*3/50 = 6 cm.

Therefore, the dimensions of a scale drawing of Elenas bedroom is length 10cm and width 6cm.

7 0
2 years ago
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Jana is ordering a list of numbers from least to greatest. StartRoot 7 squared EndRoot, StartRoot 7 EndRoot, Four-fifths, StartR
makvit [3.9K]

Answer:

The answer is D

Step-by-step explanation:

\frac{4}{5} = 0.8

\sqrt{7} = 2.64

2.64 > 0.8 because 2 is a whole number while 0.8 is a decimal

8 0
2 years ago
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Which shows one way to determine the factors of 12x3 – 2x2 + 18x – 3 by grouping?
AleksAgata [21]

we are given

12x^3-2x^2+18x-3

Firstly, we will split terms

2x^2*6x-1*2x^2+3*6x-1*3

We can group first two and last two terms

(2x^2*6x-1*2x^2)+(3*6x-1*3)

we can see that 2x^2 is common in first two terms

and 3 is common in last two terms

so, we can factor factor out 2x^2 from first group and 3 from second group

we get

=2x^2(6x-1)+3(6x-1)

we can see that each terms are multiple of 6x-1

so, we can factor out 6x-1

so, we get

12x^3-2x^2+18x-3 =(2x^2+3)(6x-1)............Answer


4 0
2 years ago
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Caroline, Colin &amp; Sarah share some money.
julia-pushkina [17]

Answer:

2/9

Step-by-step explanation:

After Caroline's share,

1 - 1/9 = 8/9 is left

Sarah gets:

1/(1+3) of 8/9

1/4 × 8/9

2/9

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2 years ago
During one month, a rental agency rented a total of 155 cars, trucks, and vans. Nine times as many cars were rented as vans, and
solong [7]

Answer:

The system of three equations is equal to

x+y+z=155

y=9x

z=3y

Step-by-step explanation:

Let

x ----> the number of cars rented during one month

y ----> the number of vans rented during one month

z ----> the number of trucks rented during one month

we know that

x+y+z=155 ----> equation A

y=9x ---> equation B

z=3y ----> equation C

8 0
2 years ago
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