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1 year ago

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You are considering purchasing a robot to help you with household chores such as vacuuming. While you are researching options,

you learn more about numeration and other bases. Many electronics are programmed in base two. Computers don't use ten digits but instead code things as 0 and 1. There are millions of little switches that are either on or off. The robot is programmed in binary numbers, or base two. The place values in a base two system are 1, 2, 4, 8, 16, etc. (powers of 2) instead of the base ten system place values of 1, 10, 100, 1000, etc. (powers of 10). How would the robot think of the number 16 in base two?

1 answer:

Vitek1552 [10]1 year ago

7 0

It will be the 5th number.
This question is basically asking what does 16 mean to 2. 16 is 2^5.

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If m(x) = x+5/x-1, and n(x) = x-3, which function has the same domain as m of n of x?

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1 year ago

Two processes are used to produce forgings used in an aircraft wing assembly. Of 200 forgings selected from process 1, 10 do not

tangare [24]

Answer:

a.

$\bar p_1=0.05\\\bar p_2=0.067$

b-Check illustration below

c.(-0.0517,0.0177

Step-by-step explanation:

a.let $p_1 \& p_2$ denote processes 1 & 2.

For $p_1$ : T1=10,n1=200

For $p_2$ :T2=20,n2=300

Therefore

$\bar p_1=\frac{t_1}{N_1}=\frac{10}{200}=0.05\\\bar p_2=\frac{t_2}{N_2}=\frac{20}{300}=0.067$

b. To test for hypothesis:-

i.

$H_0:p_1=p_2\\H_A=p_1\neq p_2\\\alpha=0.05$

ii.For a two sample Proportion test

$Z=\frac{\bar p_1-\bar p_2}{\sqrt(\bar p(1-\bar p)(\frac{1}{n_1}+\frac{1}{n_2})}\\$

iii. for $\frac{\alpha}{2}=(-1.96,+1.96)$ (0.5 alpha IS 0.025),

reject $H_o$ if $|Z|>1.96$

iv. Do not reject $H_o$ . The noncomforting proportions are not significantly different as calculated below:

$z=\frac{0.050-0.067}{\sqrt {(0.06\times0.94)\times \frac{1}{500}}}$

z=-0.78

c. $(1-\alpha).100\%$ for the p1-p2 is given as:

$(\bar p_1-\bar p_2)\pm Z_0_._5_\alpha \times \sqrt \frac{ \bar p_1(1-\bar p_1)}{n_1}+\frac{\bar p_2(1-\bar p_2)}{n_2}\\\\=(0.05-0.067)\pm 1.645 \times \sqrt \ \frac{0.05+0.95}{200}+\frac{0.067+0.933}{300}\\$

=(-0.0517,+0.0177)

*CI contains o, which implies that proportions are NOT significantly different.

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1 year ago

A baker uses 13 1/2 cups of flour to make bread. She uses 2 1/4 cups of flour to make each loaf. The baker sells 2/3 of the loav

ollegr [7]

Answer:

She sells 4 loaves of bread

Step-by-step explanation:

Lets explain how to solve the problem

→ A baker uses $13\frac{1}{2}$ cups of flour to make bread

→ She uses $2\frac{1}{4}$ cups of flour to make each loaf

From these information we can find the number of loaves of bread

she can make

∵ There are $13\frac{1}{2}$ cups of flour

∵ Each loaf of bread needs $2\frac{1}{4}$ cups of flour

∴ The number of loaves = $13\frac{1}{2}$ ÷ $2\frac{1}{4}$

To divide two mixed numbers make them improper fractions and

change the division sign to multiplication sign and reciprocal the

fraction after the division sign

∵ $13\frac{1}{2}$ = $\frac{(13)(2)+1}{2}$

∴ $13\frac{1}{2}$ = $\frac{27}{2}$

∵ $2\frac{1}{4}$ = $\frac{(2)(4)+1}{4}$

∴ $2\frac{1}{4}$ = $\frac{9}{4}$

∴ The number of loaves = $\frac{27}{2}$ × $\frac{4}{9}$

∴ The number of loaves = 6

<em>She can make 6 loaves</em>

→ The baker sells $\frac{2}{3}$ of the loaves of bread that she makes

→ We need to find the number of loves of bread she sells

∵ She sells $\frac{2}{3}$ of the loaves

∵ There are 6 loves

∴ The number of loaves she sells = 6 × $\frac{2}{3}$ = 4

<em>She sells 4 loaves of bread</em>

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1 year ago