Suppose the average price for new cars in 2012 has a mean of $30,100 and a standard deviation of $5,600. Based on this informati
1 answer:
Answer:
($13,300,$46,900)
Step-by-step explanation:
We are given the following in he question:
Mean, μ = $30,100
Standard Deviation, σ = $5,600
Chebyshev's Theorem:
- According to theorem atleast
percent of data lies within 2 standard deviations of mean.
- For k = 3,
Thus, 89% of data lies within three standard deviation of mean.
Thus, we expect at least 89% of new car prices to fall within ($13,300,$46,900)
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Answer:
P = 0.0215 = 2.15%
Step-by-step explanation:
First we need to convert the values of 900 and 975 to standard scores using the equation:
Where z is the standard value, x is the original value, is the mean and
is the standard deviation. So we have that:
standard value of 900:
standard value of 975:
Now, we just need to look at the standard distribution table (z-table) for the values of z = 2 and z = 3:
z = 2 -> p_2 = 0.9772
z = 3 -> p_3 = 0.9987
We want the interval between 900 and 975 hours, so we need the interval between z = 2 and z = 3, so we just need to subtract their p-values:
P = p_3 - p_2 = 0.9987 - 0.9772 = 0.0215
So the probability is 0.0215 = 2.15%
For this case what we should do is take into account the following conversion:
We then have the following number:
Applying the given conversion we have:
By doing the corresponding calculation we have that the standard form is given by:
Answer:
4540 million in standard form is:
We then have the following number:
Applying the given conversion we have:
By doing the corresponding calculation we have that the standard form is given by:
Answer:
4540 million in standard form is: