For a probability distribution the expected value is the summation of product of probabilities with their respective data values. Let x be the probability that Jackson goes gym for 2 days and y be the probability that he goes gym for 3 days.
For the given case we have following values and their probabilities:
0 : 0.1
2 : x
3 : y
So the expected value will be = 0(0.1) + 2(x) + 3(y)
Expected value is given to be 2.05. So we can write the equation as:
2x + 3y = 2.05 (Equation 1)
Also for a probability distribution, the sum of probabilities must always equal to 1. So we can set up the second equation as:
0.1 + x + y = 1
x + y = 0.9 (Equation 2)
From Equation 2 we can write the value of x to be x = 0.9 - y. Using this value in equation 1, we get:
2(0.9 - y) + 3y = 2.05
1.8 - 2y + 3y = 2.05
1.8 + y = 2.05
y = 0.25
Using the value of y in equation 2 we get value of x to be 0.65
Therefore we can conclude that:
The probability that Jackson goes to gym for 2 days is 0.65 and the probability that he goes to gym for 3 days is 0.25
Probably $87 based on the information I was given.
Let's say x is J because it's Lemon Juice.
It's said that the pH of J is less than 4 so: pH(J) < 4 and pH(J) is greater than 1.5 so: pH(J) > 1.5
Now we can construct:
Or simply:
We can also write this with an interval:
Hope this helps.
r3t40
Answer: 1/4
Step-by-step explanation:
Let the volume of mixture (6%fat) in cup is 100cc
x cc be the volume of cream (18% fat) in the mixture.
∴
(100−x) cc be the volume of milk (2% fat) in the mixture.
x * 0.18+(100−x) * 0.02=100
⋅0.06 or 0.18x − 0.02x = 6−2 or 0.16x
= 4 or x=25 cc = 25%
1/2 because 5/9 is equivalent to 10/18. Half of 18 is 9 and 10 is close to 9 so the nearest benchmark fraction you should round to is 1/2. Hope this helps you!
