PART I
Angular size of the minor arc .
Half of the chord an the radius makes a right angled triangle with the radius as the hypotenuse and half of the chord as one of the shorter side.
Therefore, using trigonometric ratio, sine = opp/hyp
sine θ = 8/10 where θ is half the minor angle
θ = 53.13
Therefore, the angular size of the minor arc will be 53.13 × 2 = 106.26°
PART II
The length of an arc is given by (θ/360 )× 2πr
where θ is the angle subtended by the arc to the center of the circle and r is the radius of the circle.
Therefore, length = (106.26/360) × 3.142 × 2×10
= 18.548 Inches
The area of a square is expressed as the length of the side to the power of two, A = s^2. We were given the area of the enlarged photo which is 256 in^2. Also, it was stated that the length of the enlarged photo is the length of the original photo plus ten inches. So, from these statements we can make an equation to solve for x which represents the length of the original photo.
A = s^2
where s = (x+10)
A = (x+10)^2 = 256
Solving for x,
x= 6 in.
The dimensions of the original photo is 6 x 6.
Answer:
1/3
Step-by-step explanation:
Lets start with the red ball because it is easier. You have 1/10 chances to pick the same number that is drawn randomly. Thus your base probability is .1
Now going to the white balls, you need atleast 2 numbers picked as the numbers drawn. Let's say we pick numbers 1-3. In order to win, the numbers 1 and 2, 2 and 3, 1 and 3, or 1 2 and 3 must be drawn. You can calculate the probability for each of these cases. In the case only 2 are drawn, the probability for each is 0.075. Since there are three cases that this could happen, you multiply this probability by 3, becoming 1/4. However, there is also the chance that you get all three. The probability of this is 3/10*2/9*1/8.
.225 + .1 + 0.008333 = 33.333...% or 1/3
The answer would be
You got it right
I wish i saw this when i needed jt too
Explanation
Absolutely
