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statuscvo [17]
2 years ago
13

Which scenario depicts two independent events? A teacher is calling on students to present their reports. He calls on Mario firs

t and then chooses the next presenter from the remaining students. The girls’ basketball team is playing against the boys’ basketball team. The coach chooses a captain for the girls’ team and then chooses a captain for the boys’ team. Yasmin is picking flowers from a garden to create a bouquet. She picks a flower, keeps it for the bouquet, and then she picks another. Felipe is making a dentist appointment. First he chooses the day for his appointment, and then he chooses the time from the available openings.
Mathematics
2 answers:
Vsevolod [243]2 years ago
4 0
Choosing the coaches of the basketball teams is independent because which girl he chooses does not influence nor is it influenced by the choice for the boy
Fed [463]2 years ago
3 0

B. The girls’ basketball team is playing against the boys’ basketball team. The coach chooses a captain for the girls’ team and then chooses a captain for the boys’ team

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What is the constant of the polynomial 2x3 - 8x2 + 3x - 7
Firlakuza [10]

Answer:

-7

Step-by-step explanation:

A constant number is a number that contains no variables like x and y. The only constant in that problem is -7.

8 0
1 year ago
A recipe for casserole calls for 2 cups of rice. The recipe makes 6 servings of casserole. how many cups of rice will you need t
ss7ja [257]

You will need 3.333.... cups of rice to make 10 servings of casserole.

<u><em>Explanation</em></u>

The recipe which makes 6 servings of casserole, needs 2 cups of rice.

Suppose, you need x cups of rice for making 10 servings of casserole.

Now, the equation according to <u>the ratio of "cups of rice" to the "servings of casserole" </u>will be.....

\frac{x}{10}=\frac{2}{6}\\ \\ 6x= 2*10=20\\ \\ x=\frac{20}{6}=3.333.....

So, you will need 3.333.... cups of rice to make 10 servings of casserole.


5 0
2 years ago
Kathy has $50,000 to invest today and would like to determine whether it is realistic for her to achieve her goal of buying a ho
olga_2 [115]

Answer:

a) About 12%

Step-by-step explanation:

We need to find the interest rate required to achieve her goal, so we will need to use the interest-compound formula:

FV=PV(1+i)^{n}

Where:

PV= Present Value

i= interest rate

FV= Future Value

n= number of periods

replacing the data provided:

150.000=50.000(1+i)^{10}

solving for i:

first, divide both sides by 50.000 to simplify the equation:

3=(1+i)^{10}

Take 10^{th} roots of both sides:

1+i=±\sqrt[10]{3}

solve for i:

i=±\sqrt[10]{3} -1

We get two answers, but we look for a coherent value. So we take the positive one:

i=11.6123174≈12

6 0
1 year ago
David has twice as many cousins as Becky.
Sonja [21]

Answer:

24 cugini

Step-by-step explanation:

6x2=12

12x2=24

3 0
2 years ago
Read 2 more answers
A child wanders slowly down a circular staircase from the top of a tower. With x,y,zx,y,z in feet and the origin at the base of
babymother [125]

Answer:

a) The tower is 90 feet tall

b) She reaches the bottom at t = 18 minutes.

c) Her speed at time t is 5 \sqrt[]{5} ft/minute

d) Her acceleration at time t is 10 ft/minute^2

Step-by-step explanation:

Consider the path described by the child as going down the tower to have the following parametrization \gamma(t) = (10\cos t, 10 \sin t, 90-5t)

a) Assuming that the child is at the top of the tower when she starts going down, we have that at the initial time (t=0) we will have the value of the height of the tower. That is z = 90-5*0 = 90 ft.

b) The child reaches the bottom as soon as z =0. We want to find the value of t that does that. Then we have 0 = 90-5t, which gives us t = 18 minutes.

c) Given the parametrization we are given, the velocity of the child at time t is given by \frac{d\gamma}{dt}= (\frac{d}{dt}(10\cos t), \frac{d}{dt} (10 \sin t ), \frac{d}{dt}(90-5t)) = (-10 \sin t, 10 \cos t, -5). The speed is defined as the norm of the velocity vector,

so, the speed at time t is given by v = \sqrt[]{(-10 \sin t)^2+(10 \cos t)^2+(-5)^2} = \sqrt[]{100(\sin^2 t + \cos^2 t)+25} = \sqrt[]{125}= 5 \sqrt[]{5}

d) ON the same fashion we want to know the norm of the second derivative of \gamma.

We have that \gamma ^{''}(t) =(-10\cost t, -10 \sin t , 0) so the acceleration is given by \sqrt[]{100(\cos^2 t+ \sin^2 t )} = 10 

6 0
1 year ago
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