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statuscvo [17]
2 years ago
13

Which scenario depicts two independent events? A teacher is calling on students to present their reports. He calls on Mario firs

t and then chooses the next presenter from the remaining students. The girls’ basketball team is playing against the boys’ basketball team. The coach chooses a captain for the girls’ team and then chooses a captain for the boys’ team. Yasmin is picking flowers from a garden to create a bouquet. She picks a flower, keeps it for the bouquet, and then she picks another. Felipe is making a dentist appointment. First he chooses the day for his appointment, and then he chooses the time from the available openings.
Mathematics
2 answers:
Vsevolod [243]2 years ago
4 0
Choosing the coaches of the basketball teams is independent because which girl he chooses does not influence nor is it influenced by the choice for the boy
Fed [463]2 years ago
3 0

B. The girls’ basketball team is playing against the boys’ basketball team. The coach chooses a captain for the girls’ team and then chooses a captain for the boys’ team

You might be interested in
Determine whether 52c2y4 is a monomial, binomial, trinomial, or other polynomial.
neonofarm [45]

Answer: Monomial.

Step-by-step explanation:

Ok, when we have a polynomial with only one term, this is a monomial.

If the polynomial has two terms, this is a binomial.

If the polynomial has 3 terms, this is a trinomial.

And so on.

In this particular case we have:

52*c^2*y^4

Where c and y may be variables.

We can see that here we have only one term, so this would be a monomial.

(notice that the number of variables does not affect the type of polynomial in this case, only the number of terms)

5 0
2 years ago
1. Three friends pooled their money to purchase a new game system that costs $298. One person
iragen [17]

Answer:

First person: $107

Second person: $98

Third person: $93

Step-by-step explanation:

Let be "f" the amount of money (in dollars) that the first person contributed to the purchase, "s" the amount of money (in dollars) that the second person contributed to the purchase and "t" the amount of money (in dollars) that the third person contributed to the purchase.

With the information given in the exercise, you can set up the following equations:

Equation 1 → f+s+t=298

Equation 2 → s=f-9

Equation 3 → t=f-14

Substitute the Equations 2 and 3 into the Equation 1 and then solve for "f":

f+(f-9)+(f-14)=298\\\\3f-23=298\\\\f=\frac{321}{3}\\\\f=107

Finally, substitute the value of "f" into the Equation 2 and then into the Equation 3, in order to find the values of "s" and "t".

Therefore, you get:

s=107-9\\\\s=98\\\\\\t=107-14\\\\t=93

5 0
2 years ago
Craig Campanella and Edie Hall both have night jobs. Craig has every thirteenth night and Edie has every Fifth night off. How of
Andrews [41]

Craig has every 13th night and Edie has every 5th night off.

You have to find LCM - the Least Common Multiple that is the smallest ("least") number that both 13 and 5 will divide into.

Since numbers 13 and 5 are both prime, then LCM(13,5)=13·5=65.

This means, they will have the same every 65th night off.  

6 0
2 years ago
(a) Find a vector-parametric equation r⃗ 1(t)=⟨x(t),y(t),z(t)⟩r→1(t)=⟨x(t),y(t),z(t)⟩ for the shadow of the circular cylinder x2
motikmotik

Answer: (a) r1(t) = <2cost , 0 , 2sint>

(b) <2cost , (1 - 12sint - 10cost)/8 , 2sint>

Step-by-step explanation:

x2+z2=4

a)

Now, in the xz plane, we know that y = 0...

So, x^2 + z^2 = 4 will simply be a circle centered at (0,0)..

This can be easily parameterized as

x = 2cos(t)

z = 2sin(t)

So, the required parameterization is :

r1(t) = <2cost , 0 , 2sint>

b)

Cylinder : x^2 + z^2 = 4

Plane : 5x+8y+6z=1

Easily enough, the x^2 + z^2 = 4 can again be parameterized as

x = 2cost , z = 2sint

With this, we can find y using plane equation...

5x+8y+6z=1

5(2cost) + 8y + 6(2sint) = 1

8y = 1 - 12sint - 10cost

y = (1 - 12sint - 10cost)/8

So, the parameterization is :

<2cost , (1 - 12sint - 10cost)/8 , 2sint>

6 0
2 years ago
How many 5-digit numbers are there that are divisible by either 45 or 60 but are not divisible by 90?
o-na [289]

Answer:

2500 numbers

Step-by-step explanation:

Problem;

 Solving for the number of 5-digit numbers divisible either by 45 or 60 but not divisible by 90;

 Let us approach this in a step wise manner;

  5 -digits numbers ranges from 10,000 to 99,999

To solve this problem, let us find the number of digits that are divisible by 45;  

  the first number divisible by 45 within this range is 10035

   the last number divisible by 45 in this range is 99990

    increment is 45

The total number in this range is:

           \frac{last number - first number}{increment}  + 1  = \frac{99990 - 10035}{45}  + 1

                                                      =  2000 numbers

To solve this problem, let us find the number of digits that are divisible by 60;  

  the first number divisible by 60 within this range is 10020

   the last number divisible by  in this range is 99960

    increment is 60

\frac{99990 - 10080 }{90}

The total number in this range is:

               \frac{last number - first number}{increment}  + 1  = \frac{99960 - 10020}{60}  + 1  

                                                         =  1500 numbers

To solve this problem, let us find the number of digits that are divisible by 90;  

  the first number divisible by 90 within this range is 10080

   the last number divisible by  in this range is 99990

    increment is 90

The total number in this range is:

         \frac{last number - first number}{increment} + 1  = \frac{99990 - 10080}{90} + 1

                                                  = 1000 numbers

Now solution:

  Number of 5 digits  = number of 45  + number of 60 - number of 90

                                       = 2000 + 1500  - 1000

                                        = 2500 numbers

3 0
2 years ago
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