For this problem, here’s how you do it.
Answer:
Option D
Step-by-step explanation:
The questions which involve calculating the angles and the sides of a triangle either require the sine rule or the cosine rule. In this question, the two sides that are given are adjacent to each other the given angle is the included angle. This means that the angle B is formed by the intersection of the lines a and c. Therefore, cosine rule will be used to calculate the length of b. The cosine rule is:
b^2 = a^2 + c^2 - 2*a*c*cos(B).
The question specifies that c=71, B=123°, and a=65. Plugging in the values:
b^2 = 65^2 + 71^2 - 2(65)(71)*cos(123°).
Simplifying gives:
b^2 = 14293.0182932.
Taking square root on the both sides gives b = 119.6 (rounded to the one decimal place).
This means that the Option D is the correct choice!!!
The sum of the 18 numbers is 22.5 x 18 = 405.
Let the numbers be x, x + 1, x + 2, . . ., x + 17
Sum of n term of an arithmetic sequence = n/2(a + l)
18/2(x + x + 17) = 405
9(2x + 17) = 405
2x + 17 = 405/9 = 45
2x = 45 - 17 = 28
x = 28/2 = 14
Therefore, the smallest integer is 14.
Answer:
Erin gets a result number of 5
Step-by-step explanation:
Assuming this is a 'word problem.' -- These are small numbers so you could use your hand for visual. :)
Start with 4 fingers up. (adding a negative to a positive is basically subtraction sooo...) put 3 fingers down. You now have one finger up. (subtracting a negative is just addition, think about taking those two minus signs and putting them together to get an addition sign.) now add 4 fingers to your one finger. You should be left with 5 fingers up!
Hope I helped. Hang in there, it will get easier!
