If m1 and m2 are the slopes of each line, for them to be perpendicular you gotta solve
m1 * m2 = -1
500=2.5x+200
x=the amount of desserts.
500-200=2.5x
300=2.5x
x=120
C is the answer.
System 1: The solution is (x, y) = (-4, 5)
System 2: The solution is 
<em><u>Solution:</u></em>
<em><u>Given system of equations are:</u></em>
2x + 3y = 7 ------ eqn 1
-3x - 5y = -13 --------- eqn 2
We can solve by elimination method
Multiply eqn 1 by 3
6x + 9y = 21 ------ eqn 3
Multiply eqn 2 by 2
-6x - 10y = -26 ------- eqn 4
Add eqn 3 and eqn 4
6x + 9y -6x - 10y = 21 - 26
-y = -5
y = 5
Substitute y = 5 in eqn 1
2x + 3(5) = 7
2x + 15 = 7
2x = -8
x = -4
Thus the solution is (x, y) = (-4, 5)
<h3><em><u>
Second system of equation is:</u></em></h3>
8 - y = 3x ------ eqn 1
2y + 3x = 5 ----- eqn 2
We can solve by susbtitution method
From given,
y = 8 - 3x ----- eqn 3
Substitute eqn 3 in eqn 2
2(8 - 3x) + 3x = 5
16 - 6x + 3x = 5
3x = 16 - 5
3x = 11

Substitute the above value of x in eqn 3
y = 8 - 3x

Thus the solution is 
Let x be the number of members in Daniel's tennis team.
The amount made = $582.85
Expenses (food and drinks) = $64
Balance remaining for sharing = 582.85 - 64 = $518.85
Amount received by each player = (amount made - Expenses)/Number of members = 518.85/x
Answer:
It has millions of tickets. On each ticket is written a number a dollar amount. The exact average and SD are unknown but are estimated from the sample to be $20,000 and $5,000 respectively.
Step-by-step explanation:
Given that:
sample size n = 1600
sample mean
= 20000
standard deviation = 5000
The objective is to choose from the given option about what most closely resembles the relevant box model.
The correct answer is:
It has millions of tickets. On each ticket is written a number a dollar amount. The exact average and SD are unknown but are estimated from the sample to be $20,000 and $5,000 respectively.
However, if draws are made without replacement, the best estimate of the average amount for the bride will be $20,000
Similarly, the standard error for the sample mean = 


the standard error for the sample mean = 125