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9966 [12]
2 years ago
9

A $250 gaming system is discounted by 25%. It was then discounted another 10% because the box was opened by a customer. a. The s

ale price of the gaming system is _______$ b. After both discounts are taken, the total percent discount is______$
Mathematics
1 answer:
iris [78.8K]2 years ago
3 0

Answer:

a. Sale Price=\$168.75

b. Total percent discount=32.5\%

Step-by-step explanation:

First Discount:

Initial Price=\$250

Discount=25\%

25\%\ of\ 250=\frac{25}{100}\times 250=62.5\\\\Now\ Price=250-62.5=$187.5

Second Discount:

Price=187.5\\\\Discount=10\%\\\\10\%\ of\ 187.5=\frac{10}{100}\times 187.5=18.75\\\\Now\ Sale\ Price=187.5-18.75=\$168.75

Effective Discount:

Initial Price=\$250

Final Price=\$168.75

Total discount=250-168.75=81.25

\%\ discount=\frac{81.25}{250}\times 100=32.5\%

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The graph of y=3x^2-3x-1 is shown. Use the graph to find estimates for the solutions of i)3x^2-3x+2=2 ii) 3x^2-3x-1=x+1
AlexFokin [52]

Answer:

i) (0, 2) and (1, 2), ii) (0.333, 1.333) and (1, 2).

Step-by-step explanation:

i) Let be y=3\cdot x^{2}-3\cdot x -1, if 3\cdot x^{2}-3\cdot x +2 = 2, which is equivalent to the following system of equations:

y = 3\cdot x^{2}-3\cdot x +2

y = 2

Now, this system is now represented by means of a graphing tool and whose outcome is attached below. There are two solutions: (0, 2) and (1, 2)

ii) Let be y=3\cdot x^{2}-3\cdot x -1, if 3\cdot x^{2}-3\cdot x +2 = x+1, which is equivalent to the following system of equations:

y = 3\cdot x^{2}-3\cdot x +2

y = x+1

Now, this system is now represented by means of a graphing tool and whose outcome is attached below. There are two solutions: (0.333, 1.333) and (1, 2)

7 0
2 years ago
What is 0.514 written as a power of 10? 514 x 102 514 x 103 514 x 10-3
vovikov84 [41]
0\underbrace{.514}_{3\to}=514\cdot10^{-3}
8 0
2 years ago
Read 2 more answers
In circle A shown, BC || DE , mBC=58° and mDE=142°. Determine the measure of ZCFE . Show how you arrived at your answer.
AysviL [449]

Answer:

< CFE = 40°

Step-by-step explanation:

To better understand the solution, see attachment for the diagram.

Given:

BC parallel to DE

Measure of Arc BD = 58°

Measure of Arc DE = 142°

First step: Draw a diameter that passes through the centre of the circle and name it. In this case, the diameter is line ST.

The line ST divides the arc BD and arc DE into half.

That is:

Arc SC = 1/2(arc BC) =1/2(58)

Arc SC = 29°

Arc TE = 1/2(arc DE) =1/2(142)

Arc TE = 71°

Arc SC + Arc CE + Arc TE = 180° (Sum of angles in a semicircle

29° + Arc CE  + 71° = 180°

Arc CE + 100° = 180°

Arc CE = 180-100

Arc CE = 80°

Inscribed angle = 1/2(intercepted angle)

<CFE = 1/2(Arc CE )

<CFE = 1/2(80)

< CFE = 40°

5 0
1 year ago
A library buys 36 English books, 48 Science books and 72 Mathematics books. The thickness of each book is the same. Now, the lib
fomenos

Answer:

13

Step-by-step explanation:

The GCF of 36, 48, and 72 is 12 so there will be 36 / 12 = 3 stacks of English books, 48 / 12 = 4 stacks of science books and 72 / 12 = 6 stacks of math books for a total of 3 + 4 + 6 = 13 stacks.

5 0
2 years ago
Read 2 more answers
A 12-centimeter rod is held between a flashlight and a wall as shown. Find the length of the shadow on
choli [55]

Answer:

48 cm

Step-by-step explanation:

Given:

Distance of rod from the wall = 45 cm

Distance of rod from the light = 15 cm

Length of rod = 12 cm

We can see that <DAM and <BAF are equal

Also, <DMA and <BFM are equal because they are corresponding angles

To find the length of the shadow, let's take the equation

\frac{DM}{BF} = \frac{AM}{A.F}

Where.:

DM = ½ of length of the rod = ½*12 = 6

A.F = 15 + 45 = 60 cm

AM = 15 cm

Therefore,

\frac{DM}{BF} = \frac{AM}{A.F}

= \frac{6}{BF} = \frac{15}{60}

Cross multiplying, we have:

15 * B.F = 60 * 6

15 * B.F = 360

BF = \frac{360}{15}

BF = 24 cm

The shadow on the wall =

2 * BF

= 2 * 24

= 48 cm

The shadow on the wall is 48 cm

7 0
1 year ago
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