Answer/Step-by-step explanation:
Given:
m<3 = 54°
m<2 = right angle
a. m<1 + m<2 + m<3 = 180° (angles in a straight line)
m<1 + 90° + 54° = 180° (substitution)
m<1 + 144° = 180°
m<1 = 180° - 144°
m<1 = 36°
b. m<2 = 90° (right angle)
c. m<4 = m<1 (vertical angles)
m<4 = 36° (substitution)
d. m<5 = m<2 (vertical angles)
m<5 = 90°
e. m<6 = m<3 (vertical angles)
m<6 = 54°
f. m<7 + m<6 = 180° (same side interior angles)
m<7 + 54° = 180° (substitution)
m<7 = 180 - 54
m<7 = 126°
g. m<8 = m<6 (alternate interior angles are congruent)
m<8 = 54°
h. m<9 = m<7 (vertical angles)
m<9 = 126°
i. m<10 = m<8 (vertical angles)
m<10 = 54°
j. m<11 = m<4 (alternate interior angles are congruent)
m<11 = 36° (substitution)
k. m<12 + m<11 = 180° (linear pair)
m<12 + 36° = 180° (substitution)
m<12 = 180° - 36°
m<12 = 144°
l. m<13 = m<11 (vertical angles)
m<13 = 36°
m. m<14 = m<12 (vertical angles)
m<14 = 144° (substitution)
I suppose
The vectors that span 
form a basis for 
if they are (1) linearly independent and (2) any vector in can be expressed as a linear combination of those vectors (i.e. they span ).
Compute the Wronskian determinant:
The determinant is non-zero, so the vectors are linearly independent. For this reason, we also know the dimension of is 3.
Write an arbitrary vector in as 
. Then the given vectors span if there is always a choice of scalars 
such that
which is equivalent to the system
The coefficient matrix is non-singular, so it has an inverse. Multiplying both sides by that inverse gives
so the vectors do span .
The vectors comprising form a basis for it because they are linearly independent.
Answer:
0 dollars
=E(M)
=μ
M
=−$10,000(0.81)+$40,000(0.18)+$90,000(0.01)
=−8,100+7,200+900
=0
Answer:
The probability of not rain during the entire festival is 0.19
Step-by-step explanation:
The Complement Rule states that the sum of the probabilities of an event and its complement must equal 1.
In this case we have the probability of raining of each day, we need the probability of NOT raining.
First day= 45% chance of rain, the complement is 55%
Second day 55% chance of rain, the complement is 45%
Third day a 10% chance of rain, the complement is 90%
Fourth day a 10% chance of rain, the complement is 90%
Fifth day 5% chance of rain, the complement is 95%
To get the probability of NOT raining in the entire festival is the multiplication of all the complements.
P(not raining) = 0.55 x 0.45 x 0.90 x 0.90 x 0.95= 0.19
