Apply the distributive property to create an equivalent expression. 1/3 (3j + 6) =

Elsa tries to solve the following equation, and determines there is no solution. Is she correct? Explain.

Vlad [161]

Elsa's answer is incorrect since there is a solution of the given equation. In the given logarithmic problem, we need to simplify the problem by transposing log2(3x+5) in the opposite side. The equation will now be log2x-log2(3x+5)=4. Using properties of logarithm, we further simplify the problem into a new form log (2x/6x+10)=4. Then transform the equation into base form 10^4=(2x/6x+10) and proceed in solving for x value which is equal to 1.667.

3 0

2 years ago

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A conical pile of road salt has a diameter of 112 feet and a slant height of 65 feet. After a storm, the linear dimensions of th

QveST [7]

we know that

the volume of a cone is equal to

$V= \frac{1}{3} \pi r^{2}h$

in this problem

the radius is equal to

$r= \frac{112}{2}= 56ft$

1) Find the height of the cone before the storm

Applying the Pythagorean Theorem find the height

$h^{2} = l^{2}-r^{2}$

$l=65 ft$

$h^{2} = 65^{2}-56^{2}$

$h^{2} = 1,089$

$h=33 ft$

2) Find the volume before the storm

$V= \frac{1}{3}*\pi* 56^{2}*33$

$V=34,496\pi\ ft^{3}$

3) Find the volume after the storm

After a storm, the linear dimensions of the pile are 1/3 of the original dimensions

so

r=(56/3) ft

h=(33/3)=11 ft

$V= \frac{1}{3}*\pi* (56/3)^{2}*11$

$V= 1,277.63\pi\ ft^{3}$

4) Find how this change affect the volume of the pile

Divide the volume after the storm by the volume before the storm

$\frac{1,277.63 \pi }{34,496 \pi } = \frac{1}{27}$

therefore

the answer part a) is

The volume of the pile after the storm is $\frac{1}{27}$ times the original volume

Part b) Estimate the number of lane miles that were covered with salt

5) Find the amount of salt that was used during the storm

$=34,496 \pi - 1,277.63 \pi \\= 33.218.37 \pi \\= 104,358.59\ ft^{3}$

6) Find the pounds of road salt used

$104,358.59*80=8,348,687.2\ pounds$

7) Find the number of lane miles that were covered with salt

$8,348,687.2/350=23,853.39 \ lane\ miles$

therefore

the answer part b) is

the number of lane miles that were covered with salt is $23,853.39 \ lane\ miles$

Part c) How many lane miles can be covered with the remaining salt? Round your answer to the nearest lane mile

the remaining salt is equal to $1,277.63\pi\ ft^{3}$

$1,277.63\pi\ ft^{3}=4,013.79\ ft^{3}$

8) Find the pounds of road salt

$4,013.79*80=321,103.20\ pounds$

9) Find the number of lane miles

$321,103.20/350=917.44 \ lane\ miles$

therefore

the answer part c) is

the number of lane miles is $917 \ lane\ miles$

7 0

2 years ago

Vannorman Corporation processes sugar beets in batches. A batch of sugar beets costs $78 to buy from farmers and $18 to crush in

NikAS [45]

Answer:

Results are below.

Step-by-step explanation:

We will take into account the differential costs only. Therefore, the costs of sugar beets and to crush them are irrelevant to decision making.

Beet fiber:

Sold as is= $25

Continue processing= 57 - 16= $41

It is more convenient to process further the beet fiber.

Beet juice:

Sold as is= $39

Continue processing= 84 - 22= $62

It is more convenient to process further the beet juice.

7 0

2 years ago

Lyle graphs triangle ABC on coordinate axes. He performs two transformations on this figure that result in the congruent triangl

Shtirlitz [24]

Answer:

a rotation 90˚ clockwise and then a reflection across the y-axis

Step-by-step explanation:

I'm doing the test right now

3 0

1 year ago

Why might working on a commission basis make dealing with finances more difficult

Kobotan [32]

Dealing with finances becomes more difficult when working on a commission basis because unlike working on a salary basis, there is no regular pay. A commission means that earnings are based on rate of sale or number of completed tasks. Income may be reduced if you do not sell enough, or fail to complete enough tasks.

4 0

1 year ago

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