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kramer
2 years ago
9

Stephanie has a homeowners insurance policy for her $355,000 home with an annual premium of $0.42 per $100 of value and a deduct

ible of $500. Under this policy, in the event of a major mishap, Stephanie would have a total annual out-of-pocket expense
Mathematics
2 answers:
Vikki [24]2 years ago
6 0

Stephanie has a homeowners insurance policy for her $355,000 home with an annual premium of $0.42 per $100 of value and a deductible of $500.  Under this policy, in the event of a major mishap, Stephanie would have a total annual out-of-pocket expense of [ ($355,000 / 100) * $0.42 ] + $500 = $1,991

Stephanie would like to lower her premium by increasing her deductible.  If Stephanie wants to increase her deductible to $1000, what annual premium would result in an annual out-of-pocket expense that is about the same as her current plan?

a. $0.16 per $100 of value

b. $0.28 per $100 of value

c. $0.35 per $100 of value

d. $0.46 per $100 of value

Answer: B) $0.28 per $100 of value

Oduvanchick [21]2 years ago
3 0
Step 1:
We need to find how many $100s are in $355,000 because that is the portion she is responsible to pay.

355,000 ÷ 100= 3,550

Step 2:
Multiply $0.42 by 3,550

0.42 * 3,550= $1,491 out of pocket total to pay for every $100 (before deductible)

Step 3:
Total payment = deductible plus portion to pay for every $100

Total= $1,491 + $500= $1,991 total annual out of pocket expenses

$1,991 would be the total annual out of pockets expenses in the event of a major mishap.

Hope this helps! :)
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2 years ago
Find the Jacobian ∂(x, y, z) ∂(u, v, w) for the indicated change of variables. If x = f(u, v, w), y = g(u, v, w), and z = h(u, v
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Answer:

The Jacobian ∂(x, y, z) ∂(u, v, w) for the indicated change of variables

= -3072uv

Step-by-step explanation:

<u>Step :-(i)</u>

Given  x = 1 6 (u + v)  …(i)

  Differentiating equation (i) partially with respective to 'u'

               \frac{∂x}{∂u} = 16(1)+16(0)=16

  Differentiating equation (i) partially with respective to 'v'

              \frac{∂x}{∂v} = 16(0)+16(1)=16

  Differentiating equation (i)  partially with respective to 'w'

               \frac{∂x}{∂w} = 0

Given  y = 1 6 (u − v) …(ii)

  Differentiating equation (ii) partially with respective to 'u'

               \frac{∂y}{∂u} = 16(1) - 16(0)=16

 Differentiating equation (ii) partially with respective to 'v'

               \frac{∂y}{∂v} = 16(0) - 16(1)= - 16

Differentiating equation (ii)  partially with respective to 'w'

               \frac{∂y}{∂w} = 0

Given   z = 6uvw   ..(iii)

Differentiating equation (iii) partially with respective to 'u'

               \frac{∂z}{∂u} = 6vw

Differentiating equation (iii) partially with respective to 'v'

               \frac{∂z}{∂v} =6 u (1)w=6uw

Differentiating equation (iii) partially with respective to 'w'

               \frac{∂z}{∂w} =6 uv(1)=6uv

<u>Step :-(ii)</u>

The Jacobian ∂(x, y, z)/ ∂(u, v, w) =

                                                         \left|\begin{array}{ccc}16&16&0\\16&-16&0\\6vw&6uw&6uv\end{array}\right|

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<u>Final answer</u>:-

The Jacobian ∂(x, y, z)/ ∂(u, v, w) = -3072uv

 

               

     

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Step-by-step explanation:

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Equation 2: 10(x + \frac{3}{5} ) = 2y

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Equivalent of equation 2

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