Answer:
Probability of a flowering plant bearing flowers in January if it is a peony= 70 %
Step-by-step explanation:
We know that:
Probability =Total favourable outcomes/ Total possible outcomes
Probability of flowering plants bearing flowers in January is given in the table. It means that out of 100 peony 70 peony flowers in January.
There are five kinds of flowers.
We have to select peony and find it's Probability.
As all flowers are independent, their flowering phenomenon does not depend on each other.
So,Probability of a flowering plant bearing flowers in January if it is a peony= 70 %
Answer:
a: 28 < µ < 34
Step-by-step explanation:
We need the mean, var, and standard deviation for the data set. See first attached photo for calculations for these...
We get a mean of 222/7 = 31.7143
and a sample standard deviation of: 4.3079
We can now construct our confidence interval. See the second attached photo for the construction steps.
They want a 90% confidence interval. Our sample size is 7, so since n < 30, we will use a t-score. Look up the value under the 10% area in 2 tails column, and degree of freedom is 6 (degree of freedom is always 1 less than sample size for confidence intervals when n < 30)
The t-value is: 1.943
We rounded down to the nearest person in the interval because we don't want to over estimate. It said 28.55, so more than 28 but not quite 29, so if we use 29 as the lower limit, we could over estimate. It's better to use 28 and underestimate a little when considering customer flow.
Here is a formula that you would use to find the total cost of an item that includes tax
(p × 0.07) + p
14.75x - 23=5.25x+45.2
14.75x-23-5.25x=5.25x+45.2-5.25x
14.75-5.25x=9.5
9.5x-23=45.2
9.5x-23+23=45.2+23
9.5x=68.2
9.5x/9.5=68.2/9.5
x=7.178947
Answer:
B. f(x) ≤ 0 over the interval [0, 2]. D.f(x) > 0 over the interval (–2, 0). E.f(x) ≥ 0 over the interval [2, ).
Step-by-step explanation:
Those are the 3 answers. Just did it on edge.