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vredina [299]
2 years ago
6

Which table shows a function that is decreasing only over the interval (–1, ∞)? A 2-column table with 6 rows. The first column i

s labeled x with entries negative 3, negative 2, negative 1, 0, 1, 2. The second column is labeled f of x with entries negative 1, negative 3, negative 5, negative 2, negative 1, 2. A 2-column table with 6 rows. The first column is labeled x with entries negative 3, negative 2, negative 1, 0, 1, 2. The second column is labeled f of x with entries negative 3, negative 5, negative 7, negative 6, 1, negative 1. A 2-column table with 6 rows. The first column is labeled x with entries negative 3, negative 2, negative 1, 0, 1, 2. The second column is labeled f of x with entries negative 4, negative 3, negative 1, 2, 1, negative 6. A 2-column table with 6 rows. The first column is labeled x with entries negative 3, negative 2, negative 1, 0, 1, 2. The second column is labeled f of x with entries negative 5, negative 1, 1, 0, negative 4, negative 8. Mark this and return
Mathematics
1 answer:
Lemur [1.5K]2 years ago
8 0

Answer:

B. f(x) ≤ 0 over the interval [0, 2]. D.f(x) > 0 over the interval (–2, 0). E.f(x) ≥ 0 over the interval [2, ).

Step-by-step explanation:

Those are the 3 answers. Just did it on edge.

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Sylvia invested $500 in an account compounded annually with an interest rate of 8%. Manuel invested $600 in an account with a co
Sav [38]
Syliva
T=72÷8=9 years

Manul
T=72÷7.25=9.9=10 years

Option A
8 0
2 years ago
Read 2 more answers
The basketballs Noah packed had two different prices. Of the total number of basketballs sold, 60% had a price that was $21 more
kirill115 [55]

Answer:

$(8967/n + 8.4)

Step-by-step explanation:

0.4nx + 0.6n(x+21) = 8967

nx + 12.6n = 8967

x = 8967/n - 12.6

x+21 = 8967/n + 8.4

Where n is the no. of balls

Example: if total balls were 300

n = 300

More expensive one would cost:

8967/300 + 8.4 = $38.29

8 0
2 years ago
In 154 N38 what digit should be replaced to N to make the number divisible by 3,6 and 9?​
JulsSmile [24]

Answer:

N = 6 so that number becomes divisible by 3, 6 and 9.

Step-by-step explanation:

In Number Theory there is a rule of thumb which states that sum of digits of a multiple of 3 equal 3 or a multiple of three. If we know that n = 154N38, then its sum of digits is:

x = 1 + 5+4+N+3+8

x = 21+N (Eq. 1)

We have to determine which digits corresponds to multiples of three, there are four digits:

N = 0

x = 21+0

x = 21 (3\times 7 = 21)

N = 3

x = 21+3

x = 24 (3\times 8 = 24)

N = 6

x = 21+6

x = 27 (3\times 9 = 27)

N = 9

x = 21+9

x = 30 (3\times 10 = 30)

We get the following four distinct options: 154038, 154338, 154638, 154938. Now we find which number is divisible by 6 and 9 by factor decomposition:

154038 = 2\times 3\times 25673

154338 =2\times 3\times 29 \times 887

154638 = 2\times 3\times 3\times 11\times 11\times 71

154938 = 2\times 3\times 7\times 7\times 17\times 31

It is quite evident that N = 6 so that number becomes divisible by 3, 6 and 9.

6 0
2 years ago
Carla and Marty have three straws. The straws have lengths 8 inches, 10 inches and 14 inches. They are going to use their straws
IgorLugansk [536]
Carla is correct because they will not all be exactly the same unless they choose to make them all be the same. Hope I could help! :D
6 0
2 years ago
Two samples each of size 20 are taken from independent populations assumed to be normally distributed with equal variances. The
Harlamova29_29 [7]

Answer:

t=\frac{(43.5 -40.1)-(0)}{3.678\sqrt{\frac{1}{20}+\frac{1}{20}}}=2.923

The degrees of freedom are

df=20+20-2=38

And the p value is given by:

p_v =2*P(t_{38}>2.923) =0.0058

Since the p value for this cae is lower than the significance level of 0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true means for this case are significantly different

Step-by-step explanation:

When we have two independent samples from two normal distributions with equal variances we are assuming that  

\sigma^2_1 =\sigma^2_2 =\sigma^2

And the statistic is given by this formula:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

Where t follows a t distribution with n_1+n_2 -2 degrees of freedom and the pooled variance S^2_p is given by this formula:

S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

The system of hypothesis on this case are:

Null hypothesis: \mu_1 = \mu_2

Alternative hypothesis: \mu_1 \neq \mu_2

We have the following data given:

n_1 =20 represent the sample size for group 1

n_2 =20 represent the sample size for group 2

\bar X_1 =43.5 represent the sample mean for the group 1

\bar X_2 =40.1 represent the sample mean for the group 2

s_1=4.1 represent the sample standard deviation for group 1

s_2=3.2 represent the sample standard deviation for group 2

First we can begin finding the pooled variance:

\S^2_p =\frac{(20-1)(4.1)^2 +(20 -1)(3.2)^2}{20 +20 -2}=13.525

And the deviation would be just the square root of the variance:

S_p=3.678

The statistic is givne by:

t=\frac{(43.5 -40.1)-(0)}{3.678\sqrt{\frac{1}{20}+\frac{1}{20}}}=2.923

The degrees of freedom are

df=20+20-2=38

And the p value is given by:

p_v =2*P(t_{38}>2.923) =0.0058

Since the p value for this cae is lower than the significance level of 0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true means for this case are significantly different

6 0
2 years ago
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