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2 years ago

List at least three (3) characteristics of carbon that make it a unique element.

2 answers:

7 0

1.) Carbon Compounds are the backbone of all organic compounds that are the basic building blocks of all living things.

2.) The diamond allotropic form of carbon is the hardest substance known.

3.) Carbon has the ability to form covalent bonds with other carbon atoms forming continuous chains, branches, and loops

DedPeter [7]2 years ago

3 0

Answer: Carbon occurs as a solid, liquid, and gas.

Carbon is found everywhere.

Carbon is versatile and easily combines with other elements.

Carbon bonds with other elements to form macromolecules.

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An entry level web developer's annual pay is $55,640 based on 52 weeks per year. Due to the economy, his company is having to cu

katen-ka-za [31]

Answer:

$Reduction = \$3300$

Step-by-step explanation:

Given

$Pay\ for\ 52\ weeks = \$55,640$

Required

Determine the reduction when paid is reduced to 49 weeks

First, we need to determine the weekly pay

$Weekly\ Pay = \frac{\$55,640}{52}$

$Weekly\ Pay = \$1070$

Next, is to determine the pay for 49 weeks;

$Pay = Weekly\ Pay * 49$

$Pay = \$1070 * 49$

$Pay = \$52430$

Subtract the 49 week pay from 52 weeks pay to get the payment reduction;

$Reduction = \$55640 - \$52340$

$Reduction = \$3300$

5 0

2 years ago

Which score has a higher relative position, a score of 271.2 on a test for which = 240 and , or a score of 63.6 on a test for wh

Fittoniya [83]

Answer:

The score of 271.2 on a test for which xbar = 240 and s = 24 has a higher relative position than a score of 63.6 on a test for which xbar = 60 and s = 6.

Step-by-step explanation:

Standardized score, z = (x - xbar)/s

xbar = mean, s = standard deviation.

For the first test, x = 271.2, xbar = 240, s = 24

z = (271.2 - 240)/24 = 1.3

For the second test, x = 63.6, xbar = 60, s = 6

z = (63.6 - 60)/6 = 0.6

The standardized score for the first test is more than double of the second test, hence, the score from the first test has the higher relative position.

Hope this Helps!!!

3 0

2 years ago

A pharmaceutical company proposes a new drug treatment for alleviating symptoms of PMS (premenstrual syndrome). In the first sta

Akimi4 [234]

Answer:

95% confidence interval for p, the true proportion of all women who will find success with this new treatment is [0.238 , 0.762].

Step-by-step explanation:

We are given that a pharmaceutical company proposes a new drug treatment for alleviating symptoms of PMS (premenstrual syndrome).

In the first stages of a clinical trial, it was successful for 7 out of the 14 women.

Firstly, the pivotal quantity for 95% confidence interval for the true proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of women who find success with this new treatment = $\frac{7}{14}$ = 0.50

n = sample of women = 14

Here for constructing 95% confidence interval we have used One-sample z proportion statistics.

So, 95% confidence interval for the true proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5%

level of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

95% confidence interval for p = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.50-1.96 \times {\sqrt{\frac{0.50(1-0.50)}{14} } }$ , $0.50+1.96 \times {\sqrt{\frac{0.50(1-0.50)}{14} } }$ ]

= [0.238 , 0.762]

Therefore, 95% confidence interval for p, the true proportion of all women who will find success with this new treatment is [0.238 , 0.762].

4 0

2 years ago

What is not a pair of equivalent fractions for 5/8 and 1/2

n200080 [17]

Two fractions equivalent to each: Just divide or multiply both top AND bottom by the same number.
5/6: 10/12 OR 15/18
15/30: 5/10 OR 1/2
45/60: 8/12 OR 4/6

Rewrite each pair or fractions with common denominator: Find the difference between the two bottom numbers, and multiply top and bottom number.

5/8 and 3/4: 4X2=8, 3X2=6. So, 5/8 and 6/8.
2/5 and 1/2: 2/5 and 2.5/5
9/9 and 5/7: 9/9 and ~5.7/9

Rewrite each in simple form: Find greatest common factor and divide.

9/54: 1/6
20/40: 1/2
100/110: 10/11

Are these fractions equivalent?
No. 5/1 and 5/5 are, because they are both 5 wholes. 1/5 is not because it is a fifth of a whole.

In what situation can you use multiplication to find equivalent fractions?
I'm sorry but I do not understand this question.
Source(s):I hope I helped, seeing as I have graduated with a math degree.

7 0

2 years ago

On the first day a total of 40 items were sold for $356. Define the variables and write a system of equations to find the number

Alina [70]

<h3>Question:</h3>

On the first day, a total of 40 items were sold for $356. Pies cost $10 and cakes cost $8. Define the variables, write a system of equations to find the number of cakes and pies sold, and state how many pies were sold.

<h3>Answer:</h3>

The variables are defined as:

"c" represent the number of cakes sold and "p" represent the number of pies sold

The system of equations used are:

c + p = 40 and 8c + 10p = 356

18 pies and 22 cakes were sold

<h3>Solution:</h3>

Let "c" represent the number of cakes sold

Let "p" represent the number of pies sold

Cost of 1 pie = $ 10

Cost of 1 cake = $ 8

Given that total of 40 items were sold

number of cakes + number of pies = 40

c + p = 40 ------ eqn 1

Given items were sold for $356

number of cakes sold x Cost of 1 cake + number of pies sold x Cost of 1 cake = 356

$c \times 8 + p \times 10 = 356$

8c + 10p = 356 ----- eqn 2

Let us solve eqn 1 and eqn 2

From eqn 1,

p = 40 - c ---- eqn 3

Substitute eqn 3 in eqn 2

8c + 10(40 - c) = 356

8c + 400 - 10c = 356

-2c = - 44

c = 22

Substitute c = 22 in eqn 3

p = 40 - c

p = 40 - 22

p = 18

Thus 18 pies and 22 cakes were sold

3 0

2 years ago