Can I have help on this question, please?
2 answers:
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Hence the circumference of the circle is: 6π or 18.84 units
Given:
To find:
The highest and lowest scores Sam could have made in the tournament.
Solution:
We have,
It can be written as
Add 288 on both sides.
and
and
Therefore, the highest and lowest scores Sam could have made in the tournament are 290 and 286 respectively.
Answer:
Part 1: The polygon ABCDE reflected across y-axis to get the polygon MNOPQ. So, the polygon ABCDE congruent to polygon MNOPQ.
Part 2: The vertices of polygon VWXYZ are V(1, 3), W(-1, 7), X(-7, 7), Y(-5, 3), and Z(-3, 1).
Step-by-step explanation:
Part 1:
The vertices of the polygon ABCDE are A(2, 8), B(4, 12), C(10, 12), D(8, 8), and E(6, 6).
The vertices of the polygon MNOPQ are M(-2, 8), N(-4, 12), O(-10, 12), P(-8, 8), and Q(-6, 6).
We need to find the transformation or sequence of transformations that can be performed on polygon ABCDE to show that it is congruent to polygon MNOPQ.
The relation between the vertices of ABCDE and MNOPQ are defined as
It means the polygon ABCDE reflected across y-axis to get the polygon MNOPQ. So, the polygon ABCDE congruent to polygon MNOPQ.
Part 2:
If polygon MNOPQ is translated 3 units right and 5 units down, then
Therefore the vertices of polygon VWXYZ are V(1, 3), W(-1, 7), X(-7, 7), Y(-5, 3), and Z(-3, 1).