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dimulka [17.4K]
2 years ago
5

In a golf tournament, Sam played 4 rounds and was within 2 strokes of par for all 4 rounds of the tournament. If par is 72 on th

e course he was playing, solve the equation| x - 4(72)| = 2 to determine the highest and lowest scores Sam could have made in the tournament.
Mathematics
1 answer:
In-s [12.5K]2 years ago
8 0

Given:

|x-4(72)|=2

To find:

The highest and lowest scores Sam could have made in the tournament.

Solution:

We have,

|x-4(72)|=2

|x-288|=2

It can be written as

x-288=\pm 2

Add 288 on both sides.

x=288\pm 2

x=288-2 and x=288+2

x=286 and x=290

Therefore, the highest and lowest scores Sam could have made in the tournament are 290 and 286 respectively.

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See You Later Based on a Harris Interactive poll, 20% of adults believe in reincarnation. Assume that six adults are randomly se
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Answer:

a) There is a 0.15% probability that exactly five of the selected adults believe in reincarnation.

b) 0.0064% probability that all of the selected adults believe in reincarnation.

c) There is a 0.1564% probability that at least five of the selected adults believe in reincarnation.

d) Since P(X \geq 5) < 0.05, 5 is a significantly high number of adults who believe in reincarnation in this sample.

Step-by-step explanation:

For each of the adults selected, there are only two possible outcomes. Either they believe in reincarnation, or they do not. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 6, p = 0.2

a. What is the probability that exactly five of the selected adults believe in reincarnation?

This is P(X = 5).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{6,5}.(0.2)^{5}.(0.8)^{1} = 0.0015

There is a 0.15% probability that exactly five of the selected adults believe in reincarnation.

b. What is the probability that all of the selected adults believe in reincarnation?

This is P(X = 6).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{6,6}.(0.2)^{6}.(0.8)^{0} = 0.000064

There is a 0.0064% probability that all of the selected adults believe in reincarnation.

c. What is the probability that at least five of the selected adults believe in reincarnation?

This is

P(X \geq 5) = P(X = 5) + P(X = 6) = 0.0015 + 0.000064 = 0.001564

There is a 0.1564% probability that at least five of the selected adults believe in reincarnation.

d. If six adults are randomly selected, is five a significantly high number who believe in reincarnation?

5 is significantly high if P(X \geq 5) < 0.05

We have that

P(X \geq 5) = P(X = 5) + P(X = 6) = 0.0015 + 0.000064 = 0.001564 < 0.05

Since P(X \geq 5) < 0.05, 5 is a significantly high number of adults who believe in reincarnation in this sample.

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2 years ago
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Answer:

C

Step-by-step explanation:

just did it on edgenuity.

7 0
2 years ago
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