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dimulka [17.4K]
2 years ago
7

Which expressions simplify to a rational answer? Select each correct answer. 29√⋅4√ 3√⋅16−−√ 73⋅−√3√ 5√⋅5√

Mathematics
1 answer:
PolarNik [594]2 years ago
4 0

Answer:

The correct options are 1, 3 and 4.

Step-by-step explanation:

We need to find the expressions whose simplified form is a rational number.

Rational number: If a number is defined in the form of p/q where p and q are integers and q≠0, then it is called a rational number.

For example: 0,2, 4.3 etc.

Irrational number: If a number can not defined in the form of p/q, where p and q are integers and q≠0, then it is called an irrational number.

First expression is

2\sqrt{9}\cdot \sqrt{4}=2(3)\cdot (2)\Rightarrow 6\cdot 2=12

12 is a rational number.

Second expression is

\sqrt{3}\cdot \sqrt{16}=\sqrt{3}\cdot 4\Rightarrow 4\sqrt{3}

4\sqrt{3} is an irrational number.

Third expression is

7\sqrt{3}\cdot \sqrt{3}\Rightarrow 7\cdot 3=21

21 is a rational number.

Fourth expression is

\sqrt{5}\cdot \sqrt{5}=5

5 is a rational number.

Therefore, the correct options are 1, 3 and 4.

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Find the measures of the three angles, in radians, of the triangle with the given vertices: d(1,1,1), e(1,−5,2), and f(−2,2,7).
Oduvanchick [21]

Consider triangle DEF with vertices D(1,1,1), E(1,-5,2) and F(-2,2,7).

1. Find

\overrightarrow{DE}=(1-1,-5-1,2-1)=(0,-6,1),\\ \\\overrightarrow{DF}=(-2-1,2-1,7-1)=(-3,1,6).

Then

\cos \angle D=\dfrac{0\cdot (-3)+(-6)\cdot 1+1\cdot 6}{\sqrt{0^2+(-6)^2+1^2}\cdot \sqrt{(-3)^2+1^2+6^2}}=\dfrac{0}{\sqrt{37} \cdot \sqrt{46} }=0.

2. Find

\overrightarrow{ED}=(1-1,1-(-5),1-2)=(0,6,-1),\\ \\\overrightarrow{EF}=(-2-1,2-(-5),7-2)=(-3,7,5).

Then

\cos \angle E=\dfrac{0\cdot (-2)+6\cdot 7+(-1)\cdot 5}{\sqrt{0^2+6^2+(-1)^2}\cdot \sqrt{(-3)^2+7^2+5^2}}=\dfrac{37}{\sqrt{37} \cdot \sqrt{83} }=\sqrt{\dfrac{37}{83}}.

3. Find

\overrightarrow{FE}=(1-(-2),-5-2,2-7)=(3,-7,-5),\\ \\\overrightarrow{FD}=(1-(-2),1-2,1-7)=(3,-1,-6).

Then

\cos \angle F=\dfrac{3\cdot 3+(-7)\cdot (-1)+(-5)\cdot (-6)}{\sqrt{3^2+(-7)^2+(-5)^2}\cdot \sqrt{3^2+(-1)^2+(-6)^2}}=\dfrac{46}{\sqrt{83} \cdot \sqrt{46} }=\sqrt{\dfrac{46}{83}}.

4.

\angle E=\arccos0=\dfrac{\pi}{2},\\ \\
\angle D=\arccos\letf(\sqrt{\dfrac{37}{83}}\right)\approx 0.27\pi,\\ \\
\angle F=\arccos\letf(\sqrt{\dfrac{46}{83}}\right)\approx 0.23\pi.

3 0
1 year ago
What is the greatest integer k such that 2k is a factor of 67!?
almond37 [142]

67!/2 = k = 18 235 555 459 094 342 644 124 929 548 302 732 213 583 817 657 024 762 296 850 814 250 133 981 218 471 936 000 000 000 000 000

about 1.82×10⁹⁴

7 0
2 years ago
Read 2 more answers
1. Hope's employer deposits her paycheck directly into her checking account. How much would her employer have
nadya68 [22]

Answer:

$284.79

Step-by-step explanation:

Hope has $284.79 deposited into his account.  Hope's will receive a paycheck every two weeks.                                                        

7 0
2 years ago
Read 2 more answers
Global Airlines operates two types of jet planes: jumbo and ordinary. On jumbo jets, 25% of the passengers are on business while
MArishka [77]

Answer:

Answer:

The  probability is  P(J|B) =  0.36

Step-by-step explanation:

B =business

J=jumbo

Or =ordinary

From the question we are told that  

     The proportion of the passenger on business in the ordinary jet  is P(B| Or) =  0.25

     The proportion of the passenger on business in the jumbo jet  is  P(B|J)  =  0.30

     The  proportion of the passenger on jumbo jets is  P(j) = 0.40

      The   proportion of the passenger on ordinary jets is evaluated as

         1 - P(J) =  1- 0.40  =  0.60

According to  Bayer's theorem the probability a randomly chosen business customer flying with Global is on a jumbo jet is mathematically represented as

        P(J|B) =  \frac{P(J) *  P(B|J)}{P(J ) *  P(B|J) +  P(Or ) *  P(B|Or)}

substituting values

         P(J|B) =  \frac{ 0.4 *   0.25}{0.4 *  0.25 +  0.6 * 0.3}

         P(J|B) =  0.36

Step-by-step explanation:

8 0
1 year ago
The null hypothesis says that a sprinter's reaction time follows a normal distribution with mean at most 0.150 seconds. Six meas
kkurt [141]

Answer:

The P-value is 0.0353.

Step-by-step explanation:

We are given the six measurements of a sprinter's reaction time show below;

X = 0.152, 0.154, 0.166, 0.147, 0.161, and 0.159 seconds.

Let \mu = <u><em>mean sprinter's reaction time</em></u>

So, Null Hypothesis, H_0 : \mu \leq 0.150 seconds    {means that the mean sprinter's reaction time is at most 0.150 seconds}

Alternate Hypothesis, H_A : \mu > 0.150 seconds    {means that the mean sprinter's reaction time is more than 0.150 seconds}

The test statistics that will be used here is One-sample t-test statistics because we don't know about the population standard deviation;

                             T.S.  =    ~  

where, \bar X = sample mean = \frac{\sum X}{n} = \frac{0.939}{6} = 0.1565 seconds

            s = sample standard deviation =  \sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} } = 0.0068 seconds

            n = sample of measurements = 6

So, <u><em>the test statistics</em></u> =  \frac{0.1565-0.150}{\frac{0.0068}{\sqrt{6} } }  ~  t_5

                                    =  2.341  

The value of t-test statistics is 2.341.

<em>Now, the P-value of the test statistics is given by the following formula;</em>

P-value = P( > 2.341) = 0.0353.

{Interpolating between the critical values at 5% and 2.5% significance level}

4 0
1 year ago
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