−9x+2>18 AND 13x+15≤−4

Mathematics

2 answers:

inn [45]2 years ago

8 0

Answer:

x> $\frac{16}{-9}$ and x ≤ $\frac{-19}{13}$ .

Step-by-step explanation:

Given : −9x+2>18 AND 13x+15≤−4.

To find : Solve.

Solution : We have given −9x+2>18 AND 13x+15≤−4.

For −9x + 2 > 18 .

On subtracting both sides by 2

- 9x > 18-2

- 9x > 16.

On dividing both sides by -9.

x> $\frac{16}{-9}$ .

For 13x + 15 ≤ −4.

On subtracting both sides by 15.

13 x ≤ -4 - 15.

13 x ≤ -19.

On dividing both sides by 13.

x ≤ $\frac{-19}{13}$ .

Therefore, x> $\frac{16}{-9}$ and x≤ $\frac{-19}{13}$ .

-Dominant- [34]2 years ago

3 0

Answer:

x is less than 16/9 x is greater than or equal to -19/13

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morpeh [17]

Answer:

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