Question

−9x+2>18 AND 13x+15≤−4

Answer 1

Answer:

x>$\frac{16}{-9}$ and x ≤$\frac{-19}{13}$.

Step-by-step explanation:

Given  : −9x+2>18 AND 13x+15≤−4.

To find : Solve.

Solution : We have given  −9x+2>18 AND 13x+15≤−4.

For  −9x + 2 > 18 .

On subtracting both sides by 2

- 9x > 18-2

- 9x > 16.

On dividing both sides by -9.

x>$\frac{16}{-9}$.

For  13x + 15 ≤ −4.

On subtracting both sides by 15.

13 x ≤  -4 - 15.

13 x ≤ -19.

On dividing both sides by 13.

x ≤ $\frac{-19}{13}$.

Therefore, x>$\frac{16}{-9}$ and x≤$\frac{-19}{13}$.

Answer 2

Answer:

x is less than 16/9 x is greater than or equal to -19/13