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Alex73 [517]
1 year ago
11

The vertex of a parabola that opens downward is at (0, 4). The vertex of a second parabola is at (0, –4). If the parabolas inter

sect at two points, which statement must be true?
Mathematics
2 answers:
dmitriy555 [2]1 year ago
5 0

Answer:

d. just got it right on the unit testttttt

Step-by-step explanation:

erma4kov [3.2K]1 year ago
4 0
Many statements can be true about those parabolas, so you need to include the list of choices.

This is the list of answer choices that I found for this same question:

<span>A. The second parabola opens downward.
B. The second parabola opens upward.
C. The points of intersection are on the x-axis.
D. The points of intersection are of equal distance from the y-axis.

While A, B or C may be or may not be true, D has to be true.

D. has to be true because the symetry axis of both parabolas is x = 0, so the intersection points will  be necesarily to the same distance of the x-axis and the y-axis.

Answer: </span>
<span>The points of intersection are of equal distance from the y-axis. </span>
You might be interested in
A quotient is considered rationalized if its denominator contains no
FinnZ [79.3K]

Answer:

  radicals or complex numbers

Step-by-step explanation:

A "rationalized" denominator consists entirely of a real number or variable expression with real coefficients. Preferably, any number(s) will be integer(s).

4 0
2 years ago
Al simplificar esta expresion logaritmica, cual es la forma mas simple? ​
Liula [17]

Answer:

La respuesta es

<h2>\frac{1}{2}</h2>

Step-by-step explanation:

<h3>log_{5}( \sqrt{5} )</h3>

Escribe la expresión en forma exponencial con base 5

Eso es

<h3>log_{5}(5)^{ \frac{1}{2} }</h3>

Usando las reglas de los logaritmos que

<h3>log_{ a}( {a})^{x}  = x</h3>

Simplifica la expresión

Tenemos la respuesta final como

<h3>\frac{1}{2}</h3>

Espero que esto te ayude

6 0
2 years ago
The decay of 192 mg of an isotope is given by A(t)= 192e-0.015t, where t is time in years. Find the amount left after 55 years.
statuscvo [17]

Answer:

This is a typical radioactive decay problem which uses the general form:

A = A0e^(-kt)

So, in the given equation, A0 = 192 and k = 0.015. We are to find the amount of substance left after t = 55 years. That would be represented by A. The solution is as follows:

A = 192e^(-0.015*55)

A = 84 mg

6 0
1 year ago
Mr and Mrs Smith buy tickets for themselves and their four children.
Aneli [31]
The cost of an adult ticket is £6 more than that of a child ticket, so will be denoted by c+6. Now, we are told that the cost of four child tickets and two adult tickets is £40.50, so we can put this in an equation and solve for c:
(c+6)+(c+6)+c+c+c+c=40.50
6c+12=40.50
6c=28.50
c=4.75
Therefore the cost of a child's ticket (c) is £4.75 and the cost of an adult ticket (c+6) is £10.75.
4 0
2 years ago
A million years ago, an alien species built a vertical tower on a horizontal plane. When they returned they discovered that the
velikii [3]

Answer:

\theta=cos^{-1}(\frac{2}{3})

Step-by-step explanation:

We are given that measurements of three points on the ground gave coordinates of (0,0,0),(1,2,0) and (0,2,1)

We have to find the angle by which the tower now deviate from the vertical

We find cross product of <1,2,0> and <0,2,1>

\times =\begin{vmatrix}i&j&k\\1&2&0\\0&2&1\end{vmatrix}

\times =2\hat{i}-\hat{j}+2\hat{k}

Now, we are finding the angle between  \timesand vertical vector <0,0,1>

Angle between two vectors formula

cos\theta=\frac{a.b}{\mid a\mid\cdot\mid b\mid }

Now, using this formula

cos\theta=\frac{2}{1\cdot 3}=\frac{2}{3}

\theta=cos^{-1}(\frac{2}{3})

Hence, the tower deviate from the vertical by the angle \theta=cos^{-1}(\frac{2}{3})

6 0
2 years ago
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