Step 1
<u>Find the measure of angle x</u>
we know that
If ray NP bisects <MNQ
then
m<MNQ=m<PNM+m<PNQ ------> equation A
and
m<PNM=m<PNQ -------> equation B
we have that
m<MNQ=(8x+12)°
m<PNQ=78°
so
substitute in equation A
(8x+12)=78+78-------> 8x+12=156------> 8x=156-12
8x=144------> x=18°
Step 2
<u>Find the measure of angle y</u>
we have
m<PNM=(3y-9)°
m<PNM=78°
so
3y-9=78------> 3y=87------> y=29°
therefore
<u>the answer is</u>
the measure of x is 18° and the measure of y is 29°
I had to read this a couple of times to see this was not about time, but is a right triangle problem. If the hour hand is at three, let us consider that a leg of a right triangle, we will consider the hypotenuse as the second hand.
Sketch the picture.
The hypotenuse is 9 cm. the angle is found by:
the (hour hand) is pointing directly at the 12. I expect you mean the minute hand. The angle between the minute hand and the second hand is 25/60*360 = 150 which make the angle between the hour hand and the second hand. 150 -90 =60
so the second hand and the hour hand gives us a right triangle, with a 60 degree angle and a hyp. of 9 cm.
cos 60 = x/9
9 cos 60 =x
<span>
x = 4.5 cm
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Answer:
sin−1(StartFraction 8.9 Over 10.9 EndFraction) = x
Step-by-step explanation:
From the given triangle JKL;
Hypotenuse KJ = 10.9
Length LJ is the opposite = 8.9cm
The angle LKJ is the angle opposite to side KJ = x
Using the SOH CAH TOA Identity;
sin theta = opp/hyp
sin LKJ = LJ/KJ
Sinx = 8.9/10.9
x = arcsin(8.9/10.9)
sin−1(StartFraction 8.9 Over 10.9 EndFraction) = x