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2 years ago

The data set gives the number of hours it took each of the 10 students in a cooking class to master a particular technique.

Mathematics

2 answers:

meriva2 years ago

7 0

Answer: The best measure of center for this data set is median , and its value is 4.5 .

Step-by-step explanation:

The given data set : {5, 3, 5, 30, 4, 5, 4, 3, 4, 5}

We can see that it has an outlier (i.e. 30) which is extremely large from all the values.

We know that to measure the center of tendency we measure one of three things arranged in ascending order:

Mode< Median <Mean

But mean gets affected by outlier value.

Then the best measure of center for this data set must be Median.

For this, arrange given data set in order:

{3 ,3 ,4 ,4 ,4 ,5 ,5 ,5 ,5 ,30 }

Since , the number of data values = 10 (even)

Then , Median = Mean of two middle most numbers

$\dfrac{4+5}{2}=4.5$

Hence, the best measure of center for this data set is median , and its value is 4.5 .

iris [78.8K]2 years ago

4 0

4.5 thats the answer. Im just typing so its long enough blah blah blah

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Consider the midterm and final for a statistics class. Suppose 13% of students earned an A on the midterm. Of those students who

padilas [110]

Answer:

There is a 38.97% probability that this student earned an A on the midterm.

Step-by-step explanation:

The first step is that we have to find the percentage of students who got an A on the final exam.

Suppose 13% students earned an A on the midterm. Of those students who earned an A on the midterm, 47% received an A on the final, and 11% of the students who earned lower than an A on the midterm received an A on the final.

This means that

Of the 13% of students who earned an A on the midterm, 47% received an A on the final. Also, of the 87% who did not earn an A on the midterm, 11% received an A on the final.

So, the percentage of students who got an A on the final exam is

$P_{A} = 0.13(0.47) + 0.87(0.11) = 0.1568$

To find the probability that this student earned an A on the final test also earned on the midterm, we divide the percentage of students who got an A on both tests by the percentage of students who got an A on the final test.

The percentage of students who got an A on both tests is:

$P_{AA} = 0.13(0.47) = 0.0611$

The probability that the student also earned an A on the midterm is

$P = \frac{P_{AA}}{P_{A}} = \frac{0.0611}{0.1568} = 0.3897$

There is a 38.97% probability that this student earned an A on the midterm.

5 0

2 years ago

Consider f(x) = 1.8x – 10 and g(x) = −4. A 2 column table with 6 rows. The first column, x, has the entries, negative 4, 0, 2, 4

viktelen [127]

Answer:1.8x – 10 = –4; x = 1.8 x minus 10 equals negative 4; x equals StartFraction 10 Over 2 EndFraction.

1.8 - 10= -4 x= -10/9

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

A freight carrier charges $0.57 for a package weighing up to one ounce plus and additional $0.32 for each additional ounce or fr

kherson [118]

We have to write an equation that uses this info so we can find the cost to ship that package. However, the package weight is given to us in grams and we need it in ounces. So first thing we are going to do is convert that 224 g to ounces. Use the fact that 1 g = .035274 ounces to convert. $224g*\frac{.035274oz}{1g}$ . Do the multiplication and cancel out the label of grams and we have 7.901376 ounces. Ok. We know that it costs .57 to mail the package for the first ounce. We have almost 8 ounces. So no matter what, we are paying .57. For each additional ounce we are paying .32. The number of .32's we have to spend depends upon how much the package goes over the first ounce. For the first ounce we pay .57, then for the remaining 6.901376 ounces we pay .32 per ounce. Our equation looks like this: C(x) = .32(6.901376) + .57 and we need to solve for the cost, C(x). Doing the multiplication we find that it would cost $2.78 to ship that package.

3 0

2 years ago

15 PINTS!!!!!!!!! PLZ HELP!!!!!!!! The linear function f(x) = 0.5x + 80 represents the average test score in your math class, wh

Stells [14]

Answer:

Part A: The test average for the math class after completing 2 tests is 81

Part B: The test average for the science class after completing 2 tests is 83

Part C: The science class had the higher average test score after completing the test 4.

Step-by-step explanation:

The average test score for math class is given by the linear function, f(x) = 0.5·x + 80

The data for the average test score for science g(x) are;

x, q(x)

1, 81

2, 83

3, 85

Part A: The average test score for math after completing test 2 is given as follows;

f(2) = 0.5×2 + 80 = 81

∴ The test average for the math class after completing 2 tests = 81

Part B:

The average test score for science after completing test 2 is given from the table as at x = 2, g(2) = 83

∴ The test average for the science class after completing 2 tests = 83

Part C: After completing 4 tests, we have for the math class, f(4) = 0.5×4 + 80 = 82

For the science class, it is observed that common difference between each subsequent test score average is 2, therefore, the average test score, for the fourth test is 2 added to the average test score after the third test, which gives;

Average test score, after completing the fourth test for the science class, g(4) = 85 + 2 = 87

Since g(4) > f(4) the science class had the higher average test score after completing the test 4.

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2 years ago

What is the answer to the problem 44.84 x 9.84?

Marta_Voda [28]

I hope this helps you

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2 years ago