Answer: A. A(1) = 14; A(n) = (n − 1) −4; A(n) = 14 + (n − 1)(−4)
Step-by-step explanation:
Arithmetic sequence is a sequence that is identified by their common difference. Let a be the first term, n be the number of terms and d be the common difference.
For an arithmetic sequence, common difference 'd' is added to the preceding term to get its succeeding term. For example if a is the first term of a sequence, second term will be a+d, third term will give a+d+d and so on to generate sequence of the form,
a, a+d, a+3d, a+4d...
Notice that each new term keep increasing by a common difference 'd'
The nth term of the sequence Tn will therefore give Tn = a+(n-1)d
If the initial (first) term is 14 and common difference is -4, the nth of the sequence will be gotten by substituting a = 14 and d = -4 in the general formula to give;
Tn = 14+(n-1)-4 (which gives the required answer)
Tn = 14-4n+4
Tn = 18-4n
P(both poodle) = (3/10)(3/10) = 9/100
Answer: The probability of choosing the same puppy is 9/100
Answer:
Step-by-step explanation:
given is the Differential equation in I order linear as
Take Laplace on both sides
![L(y') +4L(y) = 48L(t)\\sY(s)-y(0) +4Y(s) = 48 *\frac{1}{s^2} \\Y(s) [s+4]=\frac{48}{s^2}+9\\Y(s) = \frac{1}{s^2(s+4)}+\frac{9}{s+4}](https://tex.z-dn.net/?f=L%28y%27%29%20%2B4L%28y%29%20%3D%2048L%28t%29%5C%5CsY%28s%29-y%280%29%20%2B4Y%28s%29%20%3D%2048%20%2A%5Cfrac%7B1%7D%7Bs%5E2%7D%20%5C%5CY%28s%29%20%5Bs%2B4%5D%3D%5Cfrac%7B48%7D%7Bs%5E2%7D%2B9%5C%5CY%28s%29%20%3D%20%5Cfrac%7B1%7D%7Bs%5E2%28s%2B4%29%7D%2B%5Cfrac%7B9%7D%7Bs%2B4%7D)
Now if we take inverse we get y(t) the solution
Thus the algebraic equation would be
The dimensions of the base of Box 1 are x by 3x.
The base area of Box 1 is:
3x^2
Answer:
= (3t+2)(3t-2)(3t-4)
Step-by-step explanation:
Given the expression 27t^3 - 36t^2 - 12t + 16
On factoring:
(27t^3 - 36t^2) - (12t + 16)
= 9t²(3t-4)-4(3t-4)
= (9t²-4)(3t-4)
factoring 9t²-4
9t²-4 = (3t)² - 2²
From different of two square, a²-b² = (a+b)(a-b)
Hence (3t)² - 2² = (3t+2)(3t-2)
= (9t²-4)(3t-4)
= (3t+2)(3t-2)(3t-4)
Hence the factored form of the expression is (3t+2)(3t-2)(3t-4)
