(a) Data with the eight day's measurement.
Raw data: [60,58,64,64,68,50,57,82],
Sorted data: [50,57,58,60,64,64,68,82]
Sample size = 8 (even)
mean = 62.875
median = (60+64)/2 = 62
1st quartile = (57+58)/2 = 57.5
3rd quartile = (64+68)/2 = 66
IQR = 66 - 57.5 = 8.5
(b) Data without the eight day's measurement.
Raw data: [60,58,64,64,68,50,57]
Sorted data: [50,57,58,60,64,64,68]
Sample size = 7 (odd)
mean = 60.143
median = 60
1st quartile = 57
3rd quartile = 64
IQR = 64 -57 = 7
Answers:
1. The average is the same with or without the 8th day's data. FALSE
2. The median is the same with or without the 8th day's data. FALSE
3. The IQR decreases when the 8th day is included. FALSE
4. The IQR increases when the 8th day is included. TRUE
5. The median is higher when the 8th day is included. TRUE
Answer:
y=7600(5^(t/22))
Step-by-step explanation:
This is going to be an exponential function as it grows rapidly.
This type of question can be solved using the formula y=a(r^x), where a is the inital amount, r the factor by which the amount increases and x is the unit of time after which the amount increases.
x=t/22
a=7600
r=5
∴y=7600(5^(t/22))
Lets find all the numbers..
x (1st number)
x + 2 ( 2nd number)
x + 4 (3rd number)
x + 6 (4th number)
x + 8 (5th number)
x + 10 (6th number)
Now add all those expressions and set them equal to 270 because that is the total.
x + x + 2 + x + 4 + x + 6 + x + 8 + x + 10 = 270
6x + 30 = 270
6x = 240
x = 40
Now we will substitute 40 for x in the expression of the second number.
x + 2
40 + 2
42
So the second number is 42
Hope this helps :)
Answer:
A
Step-by-step explanation:
6/x* 5/(2x+1) = 30/ 2x^2+x
