A)
4(q -10) = 76 . . . . . Tim got 4 points for every right answer, for a score of 76. He answered correctly 10 fewer questions than were on the test.
b)
q = 10 +76/4
q = 29
The total number of questions on Tim's math test was 29.
Answer:
37,301,000
Step-by-step explanation:
The difference in population can be determined by subtracting the population of North Dakota from California
38,000,000 - 699,000 = 37,301,000
Answer:
The histogram for the given data is shown below.
Step-by-step explanation:
In a dot plot, the dots above a point represent the frequency of that number.
From the given dot plot we can make a frequency table as shown below.
Number Frequency
8 0
10 1
12 3
14 3
16 5
18 4
20 2
22 1
24 1
26 0
In histogram, each bar above a number represents the frequency of that number.
The histogram for the given data is shown below.
To answer the question, all the statements must be analyzed with the data presented in the table.
From the table we get that the team played 16 games at home and 11 games away from home.
In total, they played 27 games.
Of the 16 games at home, the team won 6. Then, the proportion of games won at home is:
6/16 = 0.375.
Of the 11 games away from home, the team won 3. Then the proportion of games won away from home is:
3/11 = 0.272.
0.375 is not twice 0.272.
Then the first statement is incorrect.
The ratio of games won at home is 6/16 = 3/8. Therefore, the second statement is incorrect. The team does not win 3/5 of the games at home.
The total number of games won is 9 and the total number of games is 27.
So, the third statement is incorrect. The team does not win half of the games.
The fourth statement is true. The team played 27 games
The fifth statement is false because the team won more than 6 games. They won 3 games away from home and 6 games at home
Finally, the sixth statement is correct, because the team lost 10 games at home and 8 away from home. However, the PERCENTAGE of games lost away from home is greater than the PERCENTAGE of games lost at home. Therefore, it is more likely that the team loses when playing away from home.
Answer:
The probability that a defective rod can be salvaged = 0.50
Step-by-step explanation:
Given that:
A machine shop produces heavy duty high endurance 20-inch rods
On occasion, the machine malfunctions and produces a groove or a chisel cut mark somewhere on the rod.
If such defective rods can be cut so that there is at least 15 consecutive inches without a groove.
Then; The defective rod can be salvaged if the groove lies on the rod between 0 and 5 inches i.e ( 20 - 15 )inches
Now:
P(X ≤ 5) = 
= 0.25
P(X ≥ 15) =
= 0.25
The probability that a defective rod can be salvaged = P(X ≤ 5) + P(X ≥ 15)
= 0.25+0.25
= 0.50
∴ The probability that a defective rod can be salvaged = 0.50
