Answer 1 with Explanation
Obtained from the question, Mario builds a triangular table to fit in a corner of the bedroom with the construction measure of 45,90 and 45 degrees which will be possible. In order to construct any physical object, proper tool are needed for accuracy of the object to built more than one of the similar table. With the help of proper instruments and measurement Mario can easily make a triangular table for his room's corner.
Answer 2 with Explanation
As Mario built the triangular table for the corner to fit his bedroom corner. He make use of the special instrument and tool for the measurement. Indeed, it is possible to construct more than one table with the angles 45,45,90 as each of them will be similar in shape but with different values of x, hence it will differ in sizes in terms of length. The length will differ as per the requirement of Mario's needs.
Swap Thiruvananthapuram for Jaipur and drop Bengaluru and Swap Mumbai for New Delhi, Thiruvananthapuram for Jaipur, and Bhubaneswar for Lucknow.this option is cheaper for thomas
The area of a square is expressed as the length of the side to the power of two, A = s^2. We were given the area of the enlarged photo which is 256 in^2. Also, it was stated that the length of the enlarged photo is the length of the original photo plus ten inches. So, from these statements we can make an equation to solve for x which represents the length of the original photo.
A = s^2
where s = (x+10)
A = (x+10)^2 = 256
Solving for x,
x= 6 in.
The dimensions of the original photo is 6 x 6.
<span>Let x = # of rides
Plan A: 10 + 3x
Plan B: 20 + x
if x < 5 rides then plan A is better buy
if x = 5 both plans are the same
if x > 5 then plan B is the best buy
Prove:
x = 6 (rides)
plan A: </span>10 + 3x = 10 + 3(6) = 10+18 = $28
plan B: 20 + x = 20 + 6 = $26
the upper bound for the length is 
.
<u>Step-by-step explanation:</u>
Lower and Upper Bounds
- The lower bound is the smallest value that will round up to the approximate value.
- The upper bound is the smallest value that will round up to the next approximate value.
Ex:- a mass of 70 kg, rounded to the nearest 10 kg, The upper bound is 75 kg, because 75 kg is the smallest mass that would round up to 80kg.
Here , A length is measured as 21cm correct to 2 significant figures. We need to find what is the upper bound for the length . let's find out:
As discussed above , upper bound for any number will be the smallest value in decimals which will round up to next integer value . So , for 21 :
⇒
21.5 cm on rounding off will give 22 cm . So , the upper bound for the length is .
