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Paladinen [302]
2 years ago
6

12700 = 23400 x (1-11.5/100)n

Mathematics
1 answer:
xxTIMURxx [149]2 years ago
6 0

Answer:

Step-by-step explanation:

889

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Announcements for 84 upcoming engineering conferences were randomly picked from a stack of IEEE Spectrum magazines. The mean len
Marina86 [1]

Answer:

Step-by-step explanation:

Hello!

You need to construct a 95% CI for the population mean of the length of engineering conferences.

The variable has a normal distribution.

The information given is:

n= 84

x[bar]= 3.94

δ= 1.28

The formula for the Confidence interval is:

x[bar]±Z_{1-\alpha/2}*(δ/n)

Lower bound(Lb): 3.698

Upper bound(Ub): 4.182

Error bound: (Ub - Lb)/2 = (4.182-3.698)/2 = 0.242

I hope it helps!

6 0
2 years ago
If line b is perpendicular to line a, and line c is perpendicular to line a, what is the slope of line c?
slega [8]

we know that

If line b is perpendicular to line a, and line c is perpendicular to line a,

then

line b and line c are parallel

and two lines parallel have the same slope

so

<u>Find the slope of the line b</u>

Let

A(-3,-2)\\B(2,3)

The formula to calculate the slope between two points is equal to

m=\frac{(y2-y1)}{(x2-x1)}

(x1,y1)=(-3,-2)\\(x2,y2)=(2,3)

substitute

m=\frac{(3+2)}{(2+3)}

m=\frac{(5)}{(5)}

m=1

therefore

<u>the answer is</u>

<u>the slope of the line c is</u>

mc=1

8 0
2 years ago
Read 2 more answers
Giselle buys two types of flowers 48 pink roses and 56 white lilies she combines the two flowers to make identical bouquets with
SSSSS [86.1K]

To solve this problem, let us first lay out all the factors of each number.

48 : 1, 2, 3, 4, 6, 8, 12, 16, 24, 48

56 : 1, 2, 4, 7, 8, 14, 28, 56

The greatest number of bouquets that can be made would be equal to the greatest common factor of the two numbers. In this case it would be 8.

 

Answer:

<span>8 bouquets</span>

7 0
2 years ago
Justin weighs 15 pounds less than Greg weighs. Half of Greg’s weight is 75 pounds less than Justin’s weight. How much does each
sp2606 [1]
Lets take Gregs weight as “x”. This means that Justins weight is x-15, and x/2 = (x-15)-75.

If we take that last equation, lets combine like terms:

x/2 = x - 15 - 75
x/2 = x - 90
Now multiply both sides by 2 to get rid of the fraction
x = 2x - 180
Subtract 2x from both sides
x - 2x = -180
-x = -180
x = 180 — this is Gregs weight

Justins weight is x-15, so 180-15, which is 165 pounds. Hope this helped.
5 0
1 year ago
A) Find a recurrence relation for the number of bit strings of length n that contain a pair of consecutive 0s.
Fed [463]

Answer:

A) a_{n} = a_{n-1} + a_{n-2} + 2^{n-2}

B) a_{0} = a_{1} = 0

C)   for n = 2

  a_{2} = 1

for n = 3

 a_{3} = 3

for n = 4

a_{4} = 8

for n = 5

a_{5} = 19

Step-by-step explanation:

A) A recurrence relation for the number of bit strings of length n that contain a  pair of consecutive Os can be represented below

if a string (n ) ends with 00 for n-2 positions there are a pair of  consecutive Os therefore there will be : 2^{n-2} strings

therefore for n ≥ 2

The recurrence relation for the number of bit strings of length 'n' that contains consecutive Os

a_{n} = a_{n-1} + a_{n-2} + 2^{n-2}

b ) The initial conditions

The initial conditions are : a_{0} = a_{1} = 0

C) The number of bit strings of length seven containing two consecutive 0s

here we apply the re occurrence relation and the initial conditions

a_{n} = a_{n-1} + a_{n-2} + 2^{n-2}

for n = 2

  a_{2} = 1

for n = 3

 a_{3} = 3

for n = 4

a_{4} = 8

for n = 5

a_{5} = 19

7 0
2 years ago
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