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Paladinen [302]
2 years ago
6

12700 = 23400 x (1-11.5/100)n

Mathematics
1 answer:
xxTIMURxx [149]2 years ago
6 0

Answer:

Step-by-step explanation:

889

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A company buys paper clips at the rate of $7.50 per box for the first 10 boxes, $5.50 per box for the next 10 boxes, and $3.50 p
BlackZzzverrR [31]

Answer:

46 boxes


Step-by-step explanation:

  • First 10 boxes can be bought for 7.5*10=75
  • Next 10 boxes can be bought for 5.5*10=55

<em>So for a total of </em><em>20 boxes, </em><em>the cost is 75+55=130</em>

<u>We have remaining 221-130=91</u>


Each additional box costs 3.5, so for 91 dollars, we can get:

\frac{91}{3.5}=26 boxes


So, total 10+10+26=46 boxes can be bought for $221.00

5 0
2 years ago
Lance is at the grocery store and has three options for buying boxed mac 3 points
Nataly [62]

Answer:b

Step-by-step explanation:

Because it b

3 0
2 years ago
The batting Wang Xiu Ying uses to fill quilts has a thermal conductivity rate of 0.030.030, point, 03 watts (\text{W})(W)left pa
alexgriva [62]

Answer:

0.0003W/cm°C

Step-by-step explanation:

The question is not properly written. Here is the correct question.

The batting wang xiu ying uses to fill quilts has a thermal conductivity rate of 0.03 watts (W) per meter(m) per degree celsius. what is the batting thermal conductivity when w/cm•c

Given the thermal conductivity in W/m°C to be 0.03W/m°C

We are to rewrite the value in W/cm°C

The difference is the unit. The only thing we need to do is to simply convert the unit (metres) in W/m°C to centimeters (cm)

Since 100cm = 1m, 0.03W/m°C can be expressed as shown below;

= 0.03W/m°C

= 0.03 × W/1m×°C

Note that 1m = 100cm, substituting this conversion into the expression, it will become;

= 0.03 × W/100cm × °C

= 0.03/100 × W/cm°C

= 0.0003W/cm°C

Hence the battling thermal conductivity in W/cm°C is 0.0003W/cm°C

4 0
2 years ago
Point b has coordinates (3,-4) and lies on the circle whose equation is x^2 + y^2= 25. If angle is drawn in a standard position
lakkis [162]
<span>Point B has coordinates (3,-4) and lies on the circle. Draw the perpendiculars from point B to the x-axis and y-axis. Denote the points of intersection with x-axis A and with y-axis C. Consider the right triangle ABO (O is the origin), by tha conditions data: AB=4 and AO=3, then by Pythagorean theorem:
</span>
<span>BO^2=AO^2+AB^2 \\ BO^2=3^2+4^2  \\ BO^2=9+16  \\ BO^2=25  \\ BO=5.
</span>
{Note, that BO is a radius of circle and it wasn't necessarily to use Pythagorean theorem to find BO}
<span>The sine of the angle BOA is</span>
\sin \angle BOA= \dfrac{AB}{BO} = \dfrac{4}{5} =0.8

Since point B is placed in the IV quadrant, the sine of the angle that is <span> drawn in a standard position with its terminal ray will be </span>
<span /><span>
</span><span>
</span>\sin \theta=-0.8 .





3 0
2 years ago
If f(x) and g(x) are inverse functions of each other, which of the following shows the graph of f(g(x))? On a coordinate plane,
Rudiy27

Answer:

its .B

Step-by-step explanation:

7 0
2 years ago
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