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SpyIntel [72]
2 years ago
5

Write an equation for the cubic polynomial function shown. To find the equation of the function, first find the of the graph.

Mathematics
2 answers:
lbvjy [14]2 years ago
5 0

The answer would look like this:

Zeros 2, 3, 5

(x-2) (x-3) (x-5) = 0

(x^2 - 2x- 3x +6) (x - 5) =0

(x^2 – 5x + 6) (x - 5) = 0

x^2 (x -5) - 5x (x - 5) + 6 (x - 5)=0

x^3 - 5x^2 -5x^2 + 25x + 6x - 30 = 0

The cubic polynomial function would be this one:

x^3 -10 x^2 + 31x - 30 = 0


check the attachment for the graph

AURORKA [14]2 years ago
3 0

answer:

Write an equation for the cubic polynomial function shown.  

To find the equation of the function, first find the <u>zeroes</u> of the graph.

What are the zeroes of the function?

2, 3, 5

hope this helps! :o)

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The point guard of a basketball team has to make a decision about whether or not to shoot a three-point attempt or pass the ball
melamori03 [73]

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5 0
2 years ago
People are arriving at a party one at a time. While waiting for more people to arrive they entertain themselves by comparing the
Marina CMI [18]

Answer:

=(k−1)*P(X>k−1) or (k−1)365k(365k−1)(k−1)!

Step-by-step explanation:

First of all, we need to find PMF

Let X = k represent the case in which there is no birthday match within (k-1) people

However, there is a birthday match when kth person arrives

Hence, there is 365^k possibilities in birthday arrangements

Supposing (k-1) dates are placed on specific days in a year

Pick one of k-1 of them & make it the date of the kth person that arrives, then:

The CDF is P(X≤k)=(1−(365k)k)/!365k, so the can obtain the PMF by  

P(X=k) =P (X≤k) − P(X≤k−1)=(1−(365k)k!/365^k)−(1−(365k−1)(k−1)!/365^(k−1))=

(k−1)/365^k * (365k−1) * (k−1)!

=(k−1)*(1−P(X≤k−1))

=(k−1)*P(X>k−1)

6 0
2 years ago
a lunch stand makes a $.75 profit on each chef's salad and $1.20 profit on each caesar salad. On a typical weekday, it sells bet
tangare [24]

Answer:

<em>50 Chef's salads and 50 Caesar salads should be prepared in order to maximize profit.</em>

Step-by-step explanation:

Suppose, the number of Chef's salad is x and the number of Caesar salad is y

On a typical weekday, it sells between 40 and 60 Chefs salads and between 35 and 50 Caesar salads.

So, the two constraints are:  40\leq x\leq 60 and  35\leq y\leq 50

The total number sold has never exceed 100 salads. So, another constraint will be:   x+y\leq 100

According to the graph of the constraints, the vertices of the common shaded region are:  (40,35), (60,35), (60,40), (50,50) and (40,50)   <em>(Refer to the attached image for the graph)</em>

The lunch stand makes a $.75 profit on each Chef's salad and $1.20 profit on each Caesar salad. So, the profit function will be:  P=0.75x+1.20y

For  (40, 35) ,   P=0.75(40)+1.20(35)=72

For  (60, 35) ,   P=0.75(60)+1.20(35)=87

For  (60, 40) ,   P=0.75(60)+1.20(40)=93

For  (50, 50) ,   P=0.75(50)+1.20(50)=97.5 <u><em>(Maximum)</em></u>

For  (40, 50) ,   P=0.75(40)+1.20(50)=90

Profit will be maximum when x=50 and y=50

Thus, 50 Chef's salads and 50 Caesar salads should be prepared in order to maximize profit.

6 0
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