Answer:
The probability that the mean amplifier output would be greater than 449.8 watts in a sample of 76 amplifiers is 0.8078.
Step-by-step explanation:
According to the Central Limit Theorem if an unknown population is selected with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from this population with replacement, then the distribution of the sample means will be approximately normally.
Then, the mean of the sample means is given by,
And the standard deviation of the sample means is given by,
The information provided is as follows:
Compute the probability that the mean amplifier output would be greater than 449.8 watts in a sample of 76 amplifiers as follows:
*Use a <em>z</em>-table.
Thus, the probability that the mean amplifier output would be greater than 449.8 watts in a sample of 76 amplifiers is 0.8078.
Answer:
35.03% probability that fewer than 7 will be carrying backpacks
Step-by-step explanation:
For each student, there are only two possible outcomes. Either they are carrying a backpack, or they are not. The probability of a student carrying a backpack is independent from other students. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which 
is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
The probability that an Oxnard University student is carrying a backpack is .70.
This means that 
If 10 students are observed at random, what is the probability that fewer than 7 will be carrying backpacks
This is 
when 
. So
35.03% probability that fewer than 7 will be carrying backpacks
Answer:
0.3
Step-by-step explanation:
the total of all probabilities is 1.00, or 100%.
In the Venn diagram, we have the probabilities 0.2, 0.4 and 0.1; these sum to
0.2+0.4+0.1 = 0.6+0.1 = 0.7.
This leaves us 1.00-0.7 = 0.3 for the remaining probability of no toppings.
N=11/60*(F-32). Multiply both sides by 60/11, so that 60/11*N=F-32. Add both sides by 32, F=60/11*N+32.
The rational numbers who absolute value is 11 by 13 are recurring decimal fraction.
Step-by-step explanation:
The rational numbers are included in the real numbers. On the other hand, they include the integers, natural numbers. In mathematics, a rational number is any number that can be expressed as the fraction p/q of two integers, a numerator p and a non-zero denominator q.
Absolute value means non-negative number with the same magnitude as a given number. In mathematics, the absolute value or modulus of a real number x, denoted |x|, is the non-negative value of x without regard to its sign.
Rational numbers consists of fractions which are of rational form following recurring and terminating fraction rules.
11 / 13 is a recurring fraction as it's rounded value is 0.846......
