It takes 40 cents worth of meat to make 2 sandwiches. What is the cost of the meat for 20 sandwiches?
2 answers:
Answer : The cost of the meat for 20 sandwiches is, 400 cents
Step-by-step explanation :
As we are given that the cost of the meat for 2 sandwiches is, 40 cents.
Now we have to determine the cost of the meat for 20 sandwiches.
As, the cost of the meat for 2 sandwiches = 40 cents
So, the cost of the meat for 20 sandwiches = cents
= 400 cents
Therefore, the cost of the meat for 20 sandwiches is, 400 cents
You might be interested in
x represents how many are sold. then multiply 80×3
then add your x together
then you must divide your x by 3440
8 is how many higher-priced speakers take you 8 and multiple it by 3 to get how many lower-priced speakers
you have 24 low priced speaker and 8 high priced speakers.
Answer:
a) 79.67% probability that a randomly selected bottle has at least 355 ml
b) 99.29% probability that the bottles of a randomly selected 6-pack of beer have an average of at least 355 ml.
c) 88.88% probability that the total amount of beer in the 6-pack is less than 2131.5 ml
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution
When the distribution is normal, we use the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this question:
a. What is the probability that a randomly selected bottle has at least 355 ml?
This is 1 subtracted by the pvalue of Z when X = 355. So
has a pvalue of 0.2033
1 - 0.2033 = 0.7967
79.67% probability that a randomly selected bottle has at least 355 ml.
b. What is the probability that the bottles of a randomly selected 6-pack of beer have an average of at least 355 ml?
Now
By the Central Limit Theorem
has a pvalue of 0.0071
1 - 0.0071 = 0.9929
99.29% probability that the bottles of a randomly selected 6-pack of beer have an average of at least 355 ml.
c. What is the probability that the total amount of beer in the 6-pack is less than 2131.5 ml?
2131.5/6 = 355.25
This is the pvalue of Z when X = 355.25.
has a pvalue of 0.1112
1 - 0.1112 = 0.8888
88.88% probability that the total amount of beer in the 6-pack is less than 2131.5 ml