All categories

2 years ago

It takes 40 cents worth of meat to make 2 sandwiches. What is the cost of the meat for 20 sandwiches?

Mathematics

2 answers:

Slav-nsk [51]2 years ago

7 0

Answer:

400 cents or four dollars

Step-by-step explanation:

If 2x10=20, then you could multiply the 40 by 10 to get the answer.

djverab [1.8K]2 years ago

5 0

Answer : The cost of the meat for 20 sandwiches is, 400 cents

Step-by-step explanation :

As we are given that the cost of the meat for 2 sandwiches is, 40 cents.

Now we have to determine the cost of the meat for 20 sandwiches.

As, the cost of the meat for 2 sandwiches = 40 cents

So, the cost of the meat for 20 sandwiches = $\frac{20}{2}\times 40$ cents

= 400 cents

Therefore, the cost of the meat for 20 sandwiches is, 400 cents

You might be interested in

FrozenT [24]

Commutative property of addition is when 3+9=12 and 9+3=12.

4 0

1 year ago

Read 2 more answers

A square rug covers 79 square feet of floor. What is the approximate length of one side of the rug? (Approximate to the nearest

Mice21 [21]

A = a^2.....where " a " is the length of one side
A = 79

79 = a^2...take sqrt of both sides, eliminating the ^2
sqrt 79 = a
8.89 = a

so the length of one side is approximately 8.89 ft <==

8 0

2 years ago

You and three friends own a paint shop. The shop's profit was $536 in the first month. You always divide the profits equally. In

alexandr1967 [171]

C. $360

$224x4=896 (total profit)

$896 (total) - $536 (first month profit) = $360 (second month profit)

4 0

2 years ago

Read 2 more answers

Jesse made 312 mini energy bars she put 24 bars in each bag she plans to sell each bag for $6

lukranit [14]

Answer:

There will be 13 such bags and Jesse will earn $ 78 by selling the energy bars.

Step-by-step explanation:

Jesse made 312 mini energy bars. She put 24 bars in each bag. So, there will be, $\frac {312}{24}$ = 13 such bags.

She plans to sell each bag for $6, so she will earn

$ $(13 \times 6)$

= $ 78 by selling the energy bars.

8 0

1 year ago

Coupons driving visits. A store randomly samples 603 shoppers over the course of a year and nds that 142 of them made their visi

s2008m [1.1K]

Answer:

The 95% confidence interval for the proportion of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 603, \pi = \frac{142}{603} = 0.2355$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 - 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2016$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 + 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2694$

The 95% confidence interval for the proportion of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694)

7 0

1 year ago