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kondaur [170]
2 years ago
11

An online store sells two types of speaker docks for smartphones. The higher-priced speaker dock sells for $190 and the lower-pr

iced speaker dock sells for $80. Last week the store sold three times as many lower-priced speaker docks as higher-priced speaker docks. Combined sales totaled $3,440. How many of each did it sell?
Mathematics
2 answers:
forsale [732]2 years ago
5 0

Answer:

8 higher-priced speaker and 24 lower-priced speaker docks are sold.

Step-by-step explanation:

Let x be the no. of  higher-priced speaker sold

We are given that the store sold three times as many lower-priced speaker docks as higher-priced speaker docks.

So,  the no. of lower-priced speaker sold = 3x

Cost of 1 higher-priced speaker dock = $190

Cost of x higher-priced speaker dock = $190x

Cost of 1 lower-priced speaker dock = $80

Cost of 3x lower-priced speaker dock = $80(3x)=$240x

So, total cost = 190x+240x=430x

We are given that Combined sales totaled $3,440.

So, 430 x = 3440

x = \frac{3440}{430}

x =8

So,The no. of higher-priced speaker sold is 8

The no. of lower-priced speaker sold = 3x = 3(8) =24

Hence 8 higher-priced speaker and 24 lower-priced speaker docks are sold.

Alex_Xolod [135]2 years ago
4 0

190x +80(3x) = 3440
x represents how many are sold. then multiply 80×3
80 \times 3 = 240
then add your x together
190x + 240x = 430x
then you must divide your x by 3440
3440 \div 430 = 8
8 is how many higher-priced speakers take you 8 and multiple it by 3 to get how many lower-priced speakers
8 \times 3 = 24
you have 24 low priced speaker and 8 high priced speakers.
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