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lidiya [134]
2 years ago
8

How well can you apply Boyle’s law to this sample of gas that experiences changes in pressure and volume? Assume that temperatur

e and number of moles of gas are constant in this problem.
Using the first volume and pressure reading on the table as V1 and P1, solve for the unknown values in the table below. Remember to use the rules of significant figures when entering your numeric response.
A:
B:
C:
D:

Mathematics
2 answers:
sukhopar [10]2 years ago
6 0

Answer:

A = 1.0 L

B = 0.50 atm

C = 0.60 atm

D = 4.0 L

Step-by-step explanation:

According to the Boyle's law, the volume of a gas is inversely proportional to its volume. If we consider an initial state (1) and a final state (2):

P₁ × V₁ = P₂ × V₂

A

P₁ × V₁ = P₂ × V₂

1.5 atm × 2.0 L = 3.0 atm × A

A = 1.0 L

B

P₁ × V₁ = P₂ × V₂

1.5 atm × 2.0 L = B × 6.0 L

B = 0.50 atm

C

P₁ × V₁ = P₂ × V₂

1.5 atm × 2.0 L = C × 5.0 L

C = 0.60 atm

D

P₁ × V₁ = P₂ × V₂

1.5 atm × 2.0 L = 0.75 atm × D

D = 4.0 L

schepotkina [342]2 years ago
6 0

Answer:

A: 1.0

B: 0.50

C: 0.60

D: 4.0

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The triangular prism shown has triangular _____face(s) and lateral face(s).
dmitriy555 [2]

Answer:

The triangular prism shown has 2 triangular face(s) and 3 lateral face(s).

The area of one triangular face is 7.5 mm²

The surface area of the triangular prism is 135 mm²

Step-by-step explanation:

A triangular face of the prism is the face that has a three sided figure while the lateral faces are faces with four-sided figure. As seen from the triangular prism, it has 2 triangular faces since it is made up of 2 right angled triangles and has 3 lateral faces since it is made up of 3 rectangles which are 4 sided each.

Area of one triangular face = \frac{1}{2} * base * height

Given base = 2.5 mm and height = 6 mm

Area of one triangular face = \frac{1}{2} *2.5 * 6\\

= 3*2.5\\= 7.5mm^{2}

Surface area of triangular prism = bh + pH

b= base of the triangle  = 2.5 mm

h- height of the triangle  = 6 mm

p= perimeter of the triangle  = base + height + slant height = 2.5+6+6.5

p = 15 mm

H= height of the prism = 8mm

Surface area of triangular prism = 2.5(6)+15(8)

Surface area of triangular prism = 15 + 120

Surface area of triangular prism = 135mm²

5 0
2 years ago
2. Which situation does have a final value of 0?
professor190 [17]

Answer:

C

Step-by-step explanation:

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Children under 10 years and older people over 65 years receive a discount on movie tickets. Let x represent the age of a person
mr_godi [17]

0<x<10

x>65

0<x<10 or x>65

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Ronnie surveyed students to find out which school sport they participated in. Below are the results from the first ten people he
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2 years ago
The equation h(t) = -16t² + 80t + 64 represented the height, in feet, of a potato t seconds after it has been launched.
Lyrx [107]

Answer:

Part A) The potato hit the ground at t=5.70 seconds (see the explanation)

Part B) The potato is 40 feet off the ground at the time t=5.28 seconds (see the explanation)

Step-by-step explanation:

we have

h(t)=-16t^2+80t+64

where

h(t) is the height of a potato in feet

t is the time in seconds

Part A)  Write an equation that can be solved to find when the potato hits the ground. Then solve the equation

we know that

When the potato hit the ground, the value of h(t) must be equal to zero

so

For h(t)=0

-16t^2+80t+64=0

Solve the quadratic equation

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-16t^2+80t+64=0

so

a=-16\\b=80\\c=64

substitute in the formula

t=\frac{-80\pm\sqrt{80^{2}-4(-16)(64)}} {2(-16)}

t=\frac{-80\pm\sqrt{10,496}} {-32}

t=\frac{-80+\sqrt{10,496}} {-32}=-0.70

t=\frac{-80-\sqrt{10,496}} {-32}=5.70

therefore

The potato hit the ground at t=5.70 seconds

Part B) Write an equation that can be solved to find when the potato is 40 feet off the ground. Then solve the equation

For h(t)=40 ft

substitute in the quadratic equation

-16t^2+80t+64=40

-16t^2+80t+24=0

Solve the quadratic equation

we have

a=-16\\b=80\\c=24

substitute in the formula

t=\frac{-80\pm\sqrt{80^{2}-4(-16)(24)}} {2(-16)}

t=\frac{-80\pm\sqrt{7,936}} {-32}

t=\frac{-80+\sqrt{7,936}} {-32}=-0.28

t=\frac{-80-\sqrt{7,936}} {-32}=5.28

therefore

The potato is 40 feet off the ground at the time t=5.28 seconds

3 0
2 years ago
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