The paper cup is 9 cm tall and the circular opening has a radius of 2.5 cm.

Lynn works as a part-time vendor selling necklaces for $15 each and bangles for $10 each. She needs to earn a minimum of $300 pe

timofeeve [1]

A,B,C,D i.e. all statements are true!

Step-by-step explanation:

According to question, Lynn works as a part-time vendor selling necklaces for $15 each and bangles for $10 each. She needs to earn a minimum of $300 per week to cover her expenses. The inequality for above scenario will be :

$15x + 10y\geq 300$ where, x is number of necklaces & y is number of bangles.

A.

Lynn will meet her goal if she sells 12 bangles and 12 necklaces. i.e. x=12 and y=12 , putting values inequality : $15(12) + 10(12) = 300$ which follows inequality . True statement!

B.

Lynn will meet her goal if she sells 20 bangles and 6 necklaces.

putting values inequality : $15(6) + 10(20) = 290$ which follows inequality . True statement!

C.

Lynn will meet her goal if she sells 6 bangles and 12 necklaces. putting values inequality : $15(12) + 10(6) = 240$ , which follows inequality . True statement!

D.

Lynn will meet her goal if she sells 2 bangles and 18 necklaces.putting values inequality : $15(18) + 10(2)=290$ , which follows inequality . True statement!

7 0

1 year ago

Read 2 more answers

Isosceles △ABC (AC=BC) is inscribed in the circle k(O). Prove that the tangent to the circle at point C is parallel to AB .

timofeeve [1]

Explanation:

Let M be the midpoint of AB. Then CM is the perpendicular bisector of AB. As such, center O is on CM, and OC is a radius (and CM). The tangent is perpendicular to that radius (and CM), so is parallel to AB, which is also perpendicular to CM.

If you need to go any further, you can show that triangles CMA and CMB are congruent, so (linear) angles CMA and CMB are congruent, hence both 90°.

5 0

1 year ago

The parent function f(x) = x3 is transformed to g(x) = (x – 1)3 + 4. Identify the graph of g(x).

Dominik [7]

we have $f(x)=x^3$ which is a cubic function.