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2 years ago

If EF bisects CD.CG = 5x - 1, GD = 7x-13, EF = 6x - 4, and GF = 13. find EG.

Mathematics

1 answer:

Iteru [2.4K]2 years ago

3 0

Answer:

EG = 19

Step-by-step explanation:

* Lets explain how to solve the problem

- If a line bisects another line that means the point of intersection

divides the second line into two equal parts

∵ EF bisects CD at G

∴ CG = GD

∵ CG = 5x - 1

∵ GD = 7x - 13

∴ 7x - 13 = 5x - 1

* Lets solve the equation

∵ 7x - 13 = 5x - 1

- Subtract 5x from both sides and add 13 to both sides

∴ 7x - 5x = 13 - 1

∴ 2x = 12

- Divide both sides by 2

∴ x = 6

- Point G divides EF into two parts EG and GF

∴ EF = EG + GF

∵ EF = 6x - 4

- Substitute the value of x to find EF

∵ x = 6

∴ EF = 6(6) - 4 = 36 - 4 = 32

∴ EF = 32

∵ GF = 13

- Substitute the values of EF and GF in the equation of EF

∴ 32 = EG + 13

- Subtract 13 from both sides

∴ 19 = EG

* EG = 19

Guest

1 year ago

where does the 32 come from

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Do not count (1p, 10p) as it is the same combination as (10p, 1p)

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Do not count (50p, 10p) nor (50p, 1p) as they are the same combinations (10p, 50p) and (1p, 50p) counted earlier:

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