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DanielleElmas [232]
2 years ago
11

Students who party before an exam are twice as likely to fail as those who don't party (and presumably study). If 20% of the stu

dents partied before the exam, what fraction of the students who failed went partying? unanswered
Mathematics
1 answer:
True [87]2 years ago
8 0

Answer:

The fraction of the students who failed to went partying = \frac{1}{10}

Step-by-step explanation:

Let total number of students = 100

No. of students partied are twice the no. of students who not partied.

⇒ No. of students partied = 2 × the no. of students who are not partied

No. of students partied before the exam = 20 % of total students

⇒ No. of students partied before the exam = \frac{20}{100} × 100

⇒ No. of students partied before the exam =  20

No. of students who not partied before the exam = \frac{20}{2} = 10

Thus the fraction of the students who failed to went partying = \frac{10}{100} = \frac{1}{10}

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A training field is formed by joining a rectangle and two semicircles, as shown below. the rectangle is 93m long and 64m wide. f
raketka [301]
If the field is 68 m wide, then each semicircle has a diameter of 68 m ,

or a radius of 68/2 = 34 m.

Area of two semicircles = Pi*R^2 = Pi(34)^2 = 3629.84 m^2
 
Area of Rectangle = LW = (95)(68) = 6460 m^2 Total Area = 6460 + 3629.84 = 10089.84 m^2
4 0
1 year ago
A company mixes pecans, cashews, peanuts, and walnuts to make a batch of mixed nuts. About 15.4% of the mixed nuts in a batch ar
Elan Coil [88]

Answer:

500 lb

Step-by-step explanation:

You have to make a proportion:

\frac{part}{whole} = \frac{percent}{100}

77 lb is part of the whole weight ( which we don't know) so 77 will go on top

The problem tells us that 15.4% of the total weight is pecans so 15.4 will go over 100 (since % are out of 100)

\frac{77}{x} = \frac{15.4}{100}

Then you cross multiply giving you: 7700 = 15.4x

then you divide 15.4 to both sides to isolate x which will give you 500

4 0
2 years ago
Mr. Jackson invested a sum of money at 6% per year, and 3 times as much at 4%
bogdanovich [222]

Mr. Jackson invested $800 at 6% per year and $ 2400  at 4 % per year

<h3><u>Solution:</u></h3>

Mr. Jackson invested a sum of money at 6% per year, and 3 times as much at 4% per year.

Let the sum invested be ‘a’ and ‘3a’ at 6% per year and 4 % per year respectively

Also, his annual return totaled $144

We can form following equation on the basis of question:-

\begin{array}{l}{\text { Then, } \frac{a \times 6 \times 1}{100}+\frac{3 a \times 4 \times 1}{100}=\$ 144} \\\\ {\frac{6 a}{100}+\frac{12 a}{100}=144} \\\\ {\frac{6 a+12 a}{100}=144} \\\\ {\frac{18 a}{100}=144} \\\\ {18 a=14400} \\\\ {a=14400 \div 18}\end{array}

a = $800

The amount of money invested at 6% = a = 800

The amount of money invested at 4 % = 3a = 3(800) = 2400

So, the amount of money invested at 6% is $800 and the amount of money invested at 4% is $ 2400

4 0
1 year ago
Of 560 samples of seafood purchased from various kinds of food stores in different regions of a country and genetically compared
frutty [35]

Answer:

a) (0.5256,0.5944)  

c) Criticism is invalid

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 560

Proportion of mislabeled = 56%

\hat{p} = 0.56

a) 90% Confidence interval:

\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

z_{critical}\text{ at}~\alpha_{0.05} = \pm 1.64

Putting the values, we get:

0.56\pm 1.64(\sqrt{\dfrac{0.56(1-0.56)}{560}}) = 0.56\pm 0.0344\\\\=(0.5256,0.5944)

b) Interpretation of confidence interval:

We are 90% confident that the true proportion of all seafood in the country that is mislabeled or misidentified is between 0.5256 and 0.5944 that is 52.56% and 59.44%.

c) Validity of criticism

Conditions for validity:

np > 10\\n(1-p)>10

Verification:

560\times 0.56 = 313.6>10\\560(1-0.56) = 246.4>10

Both the conditions are satisfied. This, the criticism is invalid.

8 0
2 years ago
A survey reported that 63.63% of moviegoers prefer action films.This percent represents a repeating decimal.write is as a fracti
Alenkasestr [34]
Let x = 63.63...(by repeating i assume you mean the 63 is repeated as 63.636363...)
therefore 100x = 6363.63..
100x-x =6300 (the recurring bit has been cancelled out which is what you should always aim to do)
99x=6300
x = 6300/99
cancel down
x = 700/11
7 0
2 years ago
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