Question

Students who party before an exam are twice as likely to fail as those who don't party (and presumably study). If 20% of the students partied before the exam, what fraction of the students who failed went partying? unanswered

Answer 1

Answer:

The fraction of the students who failed to went partying = $\frac{1}{10}$

Step-by-step explanation:

Let total number of students = 100

No. of students partied are twice the no. of students who not partied.

⇒ No. of students partied = 2 × the no. of students who are not partied

No. of students partied before the exam = 20 % of total students

⇒ No. of students partied before the exam = $\frac{20}{100}$ × 100

⇒ No. of students partied before the exam =  20

No. of students who not partied before the exam = $\frac{20}{2} = 10$

Thus the fraction of the students who failed to went partying = $\frac{10}{100} = \frac{1}{10}$